如何搜索arraylist中的元素并显示它?示例是用户想要搜索代码A25然后它将在该搜索列表中打印出他仅搜索的整个内容,输出为A25 CS 212数据结构3.
Subject CS212 = new Subject("A25","\t\tCS 212","\t\tData Structures\t\t\t\t",units);
Subject IT312 = new Subject("A26","\t\tIT 312","\t\tData Base Management System 2\t\t",units);
Subject IT313 = new Subject("A27","\t\tIT 312","\t\tData Base Management System 2\t\t",units);
Subject CS313 = new Subject("A29","\t\tCS 313","\t\tDigital Designt\t\t\t\t",units);
Subject Disc = new Subject("A30","\t\tIT 212","\t\tDiscrete Structurest\t\t",units);
Subject A31 = new Subject("A31","\t\tIT 212","\t\tDiscrete Structurest\t\t",units);
Subject Engl3 = new Subject("984","\t\tEngl 3","\t\tSpeech and oral Communicationt\t\t",units);
Subject Theo3 = new Subject("582","\t\tTheo 3","\t\tChrist and Sacramentst\t\t",units);
Subject Stat = new Subject("470","\t\tStata1","\t\tProbablility and Statisticst\t\t",units);
Subject Dota = new Subject("999","\t\tDota 2","\t\tDota Guide\t\t\t\t",units);
ArrayList<Subject> arrList = new ArrayList<Subject>();
arrList.add(CS212);
arrList.add(IT312);
arrList.add(IT313);
arrList.add(CS313);
arrList.add(Disc);
arrList.add(A31);
arrList.add(Engl3);
arrList.add(Theo3);
arrList.add(Stat);
arrList.add(Dota);
//User input that he wants to search
for(int i = 0; i < 3; i++,num++)
{
System.out.print("\t\t"+num +". ");
codeNo[i] = scan.next();
String output = Character.toUpperCase(codeNo[i].charAt(0)) + codeNo[i].substring(1);
codeNo[i] = output;
}
// This is what I tried but it doesn't work Idk why
for (Subject s : arrList) {
for(int i =0; i < codeNo.length; i++)
if (s.equals(codeNo[i])) {
System.out.println("\t\t\t"+s);
}
}
public Subject(String codeNo, String subjectID, String title , int unit)
{
//Constructor . .
}
//Desired output
Code to search
A25
A26
A27
output
A25 CS 212 Data Structures 3
A26 IT 312 Data Base Management System 2 3
A27 IT 312 Data Base Management System 2 3
答案 0 :(得分:0)
您正在尝试搜索主题的arraylist,您需要编写一个小函数来将代码字符串与类的相应字符串进行比较。您可以通过将其添加到主题类来完成此操作。
示例:
@Override
public boolean equals(String code) {
return code.equals(this.<compare to member>);
}
并将比较更改为需要匹配您匹配的代码的成员。
编辑:更简单的方法是将现有代码更改为:
if (s.code.equals(codeNo[i])) //assuming your code class member is a public string