Question

我需要得出一个结果，显示每个玩家的前3个结果的总和，并按总和对其进行排序

示例表：

David = 12   Mike = 17   John = 20   Bill = 20
David = 12   Mike = 16   John = 18   Bill = 20
David = 11   Mike = 15   John = 16
David = 10   Mike = 14   John = 16
David = 10               John = 15

结果需要显示如下：

John = 54
Mike = 50
Bill = 40
David = 35

我已经为所有活动排名（简单）：

SELECT playerName, SUM(`eventPoints`)
FROM `eventresults`
GROUP BY `playername`
ORDER BY SUM(`eventPoints`) DESC

我想用PHP代码执行以下操作：

创建一个名为top3Events的表
启动时TRUNCATE top3Events
在表eventResults
对每个新玩家名称使用计数器和重置
当计数器＆lt; = 3

运行此查询：

SELECT playerName, SUM(`eventPoints`)
FROM `top3Events`
GROUP BY `playername`
ORDER BY SUM(`eventPoints`) DESC

不确定这是否是使用此

Answer 1

我想没有人想要解决这个问题。评论中有一个很好的链接，但我可能会使用SQL和代码（PHP）的混合方法来解决这个问题。我的解决方案假设playerName是玩家的主键，并且没有非常多的玩家

我首先执行此查询（最好从players表中获取（如果有）：

SELECT DISTINCT `playerName`
FROM `eventResults`

我然后循环查询结果，构建一系列查询UNION：

SELECT `sub`.`playerName`,
    SUM(`sub`.`eventPoints`) AS `pointsSum`
FROM (
    SELECT `playerName`,
        `eventPoints`
    FROM `eventResults`
    WHERE `playerName` = '$playerName'
    ORDER BY `eventPoints` DESC
    LIMIT 3
) AS `sub`

如果每次查看时都不需要执行计算，则可以将结果存储在摘要表中，并在查看时使用它。

使用示例中的名称，生成的查询将如下所示：

SELECT `sub`.`playerName`,
    SUM(`sub`.`eventPoints`) AS `pointsSum`
FROM (
    SELECT `playerName`,
        `eventPoints`
    FROM `eventResults`
    WHERE `playerName` = 'David'
    ORDER BY `eventPoints` DESC
    LIMIT 3
) AS `sub`

UNION
SELECT `sub`.`playerName`,
    SUM(`sub`.`eventPoints`) AS `pointsSum`
FROM (
    SELECT `playerName`,
        `eventPoints`
    FROM `eventResults`
    WHERE `playerName` = 'Mike'
    ORDER BY `eventPoints` DESC
    LIMIT 3
) AS `sub`

UNION
SELECT `sub`.`playerName`,
    SUM(`sub`.`eventPoints`) AS `pointsSum`
FROM (
    SELECT `playerName`,
        `eventPoints`
    FROM `eventResults`
    WHERE `playerName` = 'John'
    ORDER BY `eventPoints` DESC
    LIMIT 3
) AS `sub`

UNION
SELECT `sub`.`playerName`,
    SUM(`sub`.`eventPoints`) AS `pointsSum`
FROM (
    SELECT `playerName`,
        `eventPoints`
    FROM `eventResults`
    WHERE `playerName` = 'Bill'
    ORDER BY `eventPoints` DESC
    LIMIT 3
) AS `sub`

ORDER BY `pointsSum` DESC

每个玩家的前3个结果并按总数排序

1 个答案: