我希望根据主键选择数据库中的多个项目。
所以,如果我有名字,我想从DB中选择imagename和refName。
我在http://www.objectdb.com/java/jpa/query/jpql/select
找到了一些东西TypedQuery<Object[]> query = em.createQuery(
"SELECT c.name, c.capital.name FROM Country AS c", Object[].class);
List<Object[]> results = query.getResultList();
for (Object[] result : results) {
System.out.println("Country: " + result[0] + ", Capital: " + result[1]);
}
哪个不起作用,而其他人似乎认为代码非常错误,所以我很好奇我将如何做到这一点?
全部谢谢!
Caused by: java.lang.IllegalArgumentException: You have attempted to set a parameter value using a name of i.name that does not exist in the query string SELECT i.name, i.refName, i.imageName FROM Items AS i.
at org.eclipse.persistence.internal.jpa.QueryImpl.setParameterInternal(QueryImpl.java:928) at org.eclipse.persistence.internal.jpa.QueryImpl.setParameterInternal(QueryImpl.java:928)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.setParameter(EJBQueryImpl.java:593)
at uploader.AdminControl.fileCreate(AdminControl.java:745)
at uploader.AdminControl.upload(AdminControl.java:660)
... 57 more
...
TypedQuery<Object[]> q = em2.createQuery("SELECT i.name, i.refName, i.imageName FROM Items AS i",Object[].class);
q.setParameter("name", plan.getFace()[i].name);
System.out.println(q);
List<Object[]> results = q.getResultList();
for (Object[] result : results)
{
bw.write(result[1].toString());
bw.write(result[2].toString());
System.out.println("result:" + result[1].toString() + "and" + result[2].toString());
}
答案 0 :(得分:2)
问题在于这段代码:
q.setParameter("i.name", plan.getFace()[i].name);
看看你的JPQL:
SELECT i.name, i.refName, i.imageName FROM Items AS i
您没有名为i.name
的参数。您应该创建一个将接收参数的。像
SELECT i.name, i.refName, i.imageName FROM Items AS i where i.name = :parameterName
确实传递了价值:
q.setParameter("parameterName", plan.getFace()[i].name);
答案 1 :(得分:0)
问题是参数名称
TypedQuery<Object[]> q = em2.createQuery("SELECT i.name, i.refName, i.imageName FROM Items WHERE i.name = :someparam AS i",Object[].class);
q.setParameter("someparam", plan.getFace()[i].name);