Question

我正在尝试使用@SendToUser回复未经身份验证的用户。

Spring 4.1.1

我正在使用新创建的Spring Boot应用程序，我唯一的配置是：

@Configuration
@EnableWebSocketMessageBroker
public class WebSocketConfig extends AbstractWebSocketMessageBrokerConfigurer {
    @Override
    public void registerStompEndpoints(StompEndpointRegistry registry) {
        registry.addEndpoint("/stomp").withSockJS();
    }
    @Override
    public void configureMessageBroker(MessageBrokerRegistry registry) {
        registry.enableSimpleBroker("/topic");
        registry.setApplicationDestinationPrefixes("/app");
        registry.setUserDestinationPrefix("/user"); 
    }
}

控制器代码：

@MessageMapping("/search")
@SendToUser("/search")
public String search(@Payload String xxx) {
    return "TEST1234";
}

JS：

var socket = new SockJS('/webapp/stomp');
stompClient = Stomp.over(socket);
stompClient.connect({}, function(frame) {
    stompClient.subscribe('/user/search', function(data){
        alert(data.body);
    });
});

春季输出：

DEBUG  org.springframework.web.servlet.DispatcherServlet: 996 - Successfully completed request
DEBUG   o.s.w.s.handler.LoggingWebSocketHandlerDecorator:  45 - New WebSocketServerSockJsSession[id=shizav88]
DEBUG       o.s.m.simp.broker.SimpleBrokerMessageHandler: 158 - Processing CONNECT session=shizav88
DEBUG      o.s.m.simp.user.UserDestinationMessageHandler: 187 - Translated /user/search -> [/search-usershizav88]

JS：

var name = document.getElementById('name').value;
stompClient.send("/app/search", {}, "test"));

春季输出：

DEBUG     o.s.m.s.a.s.SimpAnnotationMethodMessageHandler: 348 - Searching methods to handle SEND /app/search session=shizav88
DEBUG     o.s.m.s.a.s.SimpAnnotationMethodMessageHandler: 446 - Invoking de.benneq.next.search.SearchController#search[1 args]
DEBUG   o.s.b.factory.support.DefaultListableBeanFactory: 247 - Returning cached instance of singleton bean 'searchController'
DEBUG      o.s.m.simp.user.UserDestinationMessageHandler: 187 - Translated /user/shizav88/search -> [/search-usershizav88]

对我来说，看起来Spring将订阅映射到/search-usershizav88。然后使用/search-usershizav88发送响应。但我的JS客户端没有收到任何东西。

有什么问题？

Answer 1

现在我开始工作，但我真的不知道为什么：

配置：

@Configuration
@EnableWebSocketMessageBroker
public class WebSocketConfig extends AbstractWebSocketMessageBrokerConfigurer {
    @Override
    public void registerStompEndpoints(StompEndpointRegistry registry) {
        registry.addEndpoint("/stomp").withSockJS();
    }
    @Override
    public void configureMessageBroker(MessageBrokerRegistry registry) {
        registry.enableSimpleBroker("/queue", "/topic"); // <- added "/queue"
        registry.setApplicationDestinationPrefixes("/app");
        registry.setUserDestinationPrefix("/user"); 
    }
}

控制器：

@MessageMapping("/search")
@SendToUser // <- maps to "/user/queue/search"
public String search(@Payload String xxx) {
    return "TEST1234";
}

JS：

stompClient.subscribe('/user/queue/search', function(data){
    alert(data.body);
});

Spring输出：

DEBUG  org.springframework.web.servlet.DispatcherServlet: 996 - Successfully completed request
DEBUG   o.s.w.s.handler.LoggingWebSocketHandlerDecorator:  45 - New WebSocketServerSockJsSession[id=fkbmnpkj]
DEBUG       o.s.m.simp.broker.SimpleBrokerMessageHandler: 158 - Processing CONNECT session=fkbmnpkj
DEBUG      o.s.m.simp.user.UserDestinationMessageHandler: 187 - Translated /user/queue/search -> [/queue/search-userfkbmnpkj]
DEBUG       o.s.m.simp.broker.SimpleBrokerMessageHandler: 175 - Processing SUBSCRIBE /queue/search-userfkbmnpkj id=sub-0 session=fkbmnpkj

现在日志中还有一行，表示它是处理SUBSCRIBE / queue / search-userfkbmnpkj id = sub-0 session = fkbmnpkj

之前失踪了。

如果有人可以解释为什么我需要/queue映射才能使其正常工作，那仍然会很好。

Answer 2

在第一篇文章中，您订阅了“/ user / search”。在第二个“/ user / queue / search”中。我检查了“/ user / topic / search”，它也有效。所以解决方案是使用有效的主题名称。没有魔法......

Spring Stomp @SendToUser与未经身份验证的用户无法正常工作

2 个答案:

配置：

控制器：

JS：

Spring输出：