Question

我正在计算'from'和'to'日期之间的天数。例如，如果起始日期是2010年4月13日，并且截止日期是15/04/2010，则结果应为
如何使用JavaScript获得结果？

Answer 1

var oneDay = 24*60*60*1000; // hours*minutes*seconds*milliseconds
var firstDate = new Date(2008,01,12);
var secondDate = new Date(2008,01,22);

var diffDays = Math.round(Math.abs((firstDate.getTime() - secondDate.getTime())/(oneDay)));

Answer 2

这是一个执行此操作的函数：

function days_between(date1, date2) {

    // The number of milliseconds in one day
    var ONE_DAY = 1000 * 60 * 60 * 24;

    // Convert both dates to milliseconds
    var date1_ms = date1.getTime();
    var date2_ms = date2.getTime();

    // Calculate the difference in milliseconds
    var difference_ms = Math.abs(date1_ms - date2_ms);

    // Convert back to days and return
    return Math.round(difference_ms/ONE_DAY);

}

Answer 3

这是我使用的。如果您只是减去日期，它将无法在夏令时间界限内工作（例如4月1日至4月30日或10月1日至10月31日）。这会减少所有时间，以确保您获得一天，并通过使用UTC消除任何DST问题。

var nDays = (    Date.UTC(EndDate.getFullYear(), EndDate.getMonth(), EndDate.getDate()) -
                 Date.UTC(StartDate.getFullYear(), StartDate.getMonth(), StartDate.getDate())) / 86400000;

作为一个功能：

function DaysBetween(StartDate, EndDate) {
  // The number of milliseconds in all UTC days (no DST)
  const oneDay = 1000 * 60 * 60 * 24;

  // A day in UTC always lasts 24 hours (unlike in other time formats)
  const start = Date.UTC(EndDate.getFullYear(), EndDate.getMonth(), EndDate.getDate());
  const end = Date.UTC(StartDate.getFullYear(), StartDate.getMonth(), StartDate.getDate());

  // so it's safe to divide by 24 hours
  return (start - end) / oneDay;
}

Answer 4

这是我的实施：

function daysBetween(one, another) {
  return Math.round(Math.abs((+one) - (+another))/8.64e7);
}

+<date>对整数表示进行类型强制，与<date>.getTime()具有相同的效果，8.64e7是一天中的毫秒数。

Answer 5

调整以允许夏令时差异。试试这个：

  function daysBetween(date1, date2) {

 // adjust diff for for daylight savings
 var hoursToAdjust = Math.abs(date1.getTimezoneOffset() /60) - Math.abs(date2.getTimezoneOffset() /60);
 // apply the tz offset
 date2.addHours(hoursToAdjust); 

    // The number of milliseconds in one day
    var ONE_DAY = 1000 * 60 * 60 * 24

    // Convert both dates to milliseconds
    var date1_ms = date1.getTime()
    var date2_ms = date2.getTime()

    // Calculate the difference in milliseconds
    var difference_ms = Math.abs(date1_ms - date2_ms)

    // Convert back to days and return
    return Math.round(difference_ms/ONE_DAY)

}

// you'll want this addHours function too 

Date.prototype.addHours= function(h){
    this.setHours(this.getHours()+h);
    return this;
}

Answer 6

我已经为另一个帖子写了这个解决方案，他们问如何计算两个日期之间的差异，所以我分享了我准备的内容：

// Here are the two dates to compare
var date1 = '2011-12-24';
var date2 = '2012-01-01';

// First we split the values to arrays date1[0] is the year, [1] the month and [2] the day
date1 = date1.split('-');
date2 = date2.split('-');

// Now we convert the array to a Date object, which has several helpful methods
date1 = new Date(date1[0], date1[1], date1[2]);
date2 = new Date(date2[0], date2[1], date2[2]);

// We use the getTime() method and get the unixtime (in milliseconds, but we want seconds, therefore we divide it through 1000)
date1_unixtime = parseInt(date1.getTime() / 1000);
date2_unixtime = parseInt(date2.getTime() / 1000);

// This is the calculated difference in seconds
var timeDifference = date2_unixtime - date1_unixtime;

// in Hours
var timeDifferenceInHours = timeDifference / 60 / 60;

// and finaly, in days :)
var timeDifferenceInDays = timeDifferenceInHours  / 24;

alert(timeDifferenceInDays);

您可以跳过代码中的一些步骤，我已编写它以便于理解。

您可以在此处找到一个正在运行的示例：http://jsfiddle.net/matKX/

Answer 7

从我的小日期差异计算器：

var startDate = new Date(2000, 1-1, 1);  // 2000-01-01
var endDate =   new Date();              // Today

// Calculate the difference of two dates in total days
function diffDays(d1, d2)
{
  var ndays;
  var tv1 = d1.valueOf();  // msec since 1970
  var tv2 = d2.valueOf();

  ndays = (tv2 - tv1) / 1000 / 86400;
  ndays = Math.round(ndays - 0.5);
  return ndays;
}

所以你打电话：

var nDays = diffDays(startDate, endDate);

（http://david.tribble.com/src/javascript/jstimespan.html的完整来源。）

<强>附录

可以通过更改以下行来改进代码：

  var tv1 = d1.getTime();  // msec since 1970
  var tv2 = d2.getTime();

如何计算两个日期之间的天数？

7 个答案: