有人建议将一个对象的值映射到另一个对象吗?我想要一个使用反射的实用程序类,如果有一个具有相同名称的公共属性,它将获取两个对象并将值从第一个对象复制到第二个对象。
我有两个从Web服务代理生成的实体,所以我不能更改父类或者修改接口或类似的东西。但我知道这两个对象具有相同的公共属性。
答案 0 :(得分:41)
一起扔起来应该很简单......
public static void CopyPropertyValues(object source, object destination)
{
var destProperties = destination.GetType().GetProperties();
foreach (var sourceProperty in source.GetType().GetProperties())
{
foreach (var destProperty in destProperties)
{
if (destProperty.Name == sourceProperty.Name &&
destProperty.PropertyType.IsAssignableFrom(sourceProperty.PropertyType))
{
destProperty.SetValue(destination, sourceProperty.GetValue(
source, new object[] { }), new object[] { });
break;
}
}
}
}
答案 1 :(得分:18)
Jon Skeet和Marc Gravell有一个名为MiscUtil的图书馆。在MiscUtil.Reflection
内,有一个名为PropertyCopy
的类,它完全按照您的描述进行操作。它仅适用于.NET 3.5。
它的工作原理是遍历SourceType的公共属性,通过名称与TargetType的公共属性进行匹配,确保每个属性都可以从源分配到目标,然后创建并缓存复制器功能对于这两种类型(所以你不是每次都做这些反射)。我已经在生产代码中使用它并且可以保证它的优点。
嘿,我想我只是发布他们的简洁代码(不到100行/评论)。可以在here找到此代码的许可证:
using System;
using System.Collections.Generic;
using System.Linq.Expressions;
using System.Reflection;
namespace MiscUtil.Reflection
{
/// <summary>
/// Generic class which copies to its target type from a source
/// type specified in the Copy method. The types are specified
/// separately to take advantage of type inference on generic
/// method arguments.
/// </summary>
public static class PropertyCopy<TTarget> where TTarget : class, new()
{
/// <summary>
/// Copies all readable properties from the source to a new instance
/// of TTarget.
/// </summary>
public static TTarget CopyFrom<TSource>(TSource source) where TSource : class
{
return PropertyCopier<TSource>.Copy(source);
}
/// <summary>
/// Static class to efficiently store the compiled delegate which can
/// do the copying. We need a bit of work to ensure that exceptions are
/// appropriately propagated, as the exception is generated at type initialization
/// time, but we wish it to be thrown as an ArgumentException.
/// </summary>
private static class PropertyCopier<TSource> where TSource : class
{
private static readonly Func<TSource, TTarget> copier;
private static readonly Exception initializationException;
internal static TTarget Copy(TSource source)
{
if (initializationException != null)
{
throw initializationException;
}
if (source == null)
{
throw new ArgumentNullException("source");
}
return copier(source);
}
static PropertyCopier()
{
try
{
copier = BuildCopier();
initializationException = null;
}
catch (Exception e)
{
copier = null;
initializationException = e;
}
}
private static Func<TSource, TTarget> BuildCopier()
{
ParameterExpression sourceParameter = Expression.Parameter(typeof(TSource), "source");
var bindings = new List<MemberBinding>();
foreach (PropertyInfo sourceProperty in typeof(TSource).GetProperties())
{
if (!sourceProperty.CanRead)
{
continue;
}
PropertyInfo targetProperty = typeof(TTarget).GetProperty(sourceProperty.Name);
if (targetProperty == null)
{
throw new ArgumentException("Property " + sourceProperty.Name + " is not present and accessible in " + typeof(TTarget).FullName);
}
if (!targetProperty.CanWrite)
{
throw new ArgumentException("Property " + sourceProperty.Name + " is not writable in " + typeof(TTarget).FullName);
}
if (!targetProperty.PropertyType.IsAssignableFrom(sourceProperty.PropertyType))
{
throw new ArgumentException("Property " + sourceProperty.Name + " has an incompatible type in " + typeof(TTarget).FullName);
}
bindings.Add(Expression.Bind(targetProperty, Expression.Property(sourceParameter, sourceProperty)));
}
Expression initializer = Expression.MemberInit(Expression.New(typeof(TTarget)), bindings);
return Expression.Lambda<Func<TSource,TTarget>>(initializer, sourceParameter).Compile();
}
}
}
}
答案 2 :(得分:11)
我们使用Automapper。它的效果非常好。
答案 3 :(得分:5)
我已经改进了Robinson的答案并将其重构为Object类型的扩展方法,非常方便:
public static void CopyPropertyValues( this object destination, object source )
{
if ( !( destination.GetType ().Equals ( source.GetType () ) ) )
throw new ArgumentException ( "Type mismatch" );
if ( destination is IEnumerable )
{
var dest_enumerator = (destination as IEnumerable).GetEnumerator();
var src_enumerator = (source as IEnumerable).GetEnumerator();
while ( dest_enumerator.MoveNext () && src_enumerator.MoveNext () )
dest_enumerator.Current.CopyPropertyValues ( src_enumerator.Current );
}
else
{
var destProperties = destination.GetType ().GetRuntimeProperties ();
foreach ( var sourceProperty in source.GetType ().GetRuntimeProperties () )
{
foreach ( var destProperty in destProperties )
{
if ( destProperty.Name == sourceProperty.Name
&& destProperty.PropertyType.GetTypeInfo ()
.IsAssignableFrom ( sourceProperty.PropertyType.GetTypeInfo () ) )
{
destProperty.SetValue ( destination, sourceProperty.GetValue (
source, new object[] { } ), new object[] { } );
break;
}
}
}
}
}
答案 4 :(得分:2)
我在Marc Gravell阅读using Expression<T>
to do this后不久发表了关于this article的博文。
它看起来(根据另一个答案)可能类似于Jon Skeet和Marc的MiscUtil中的那个。
答案 5 :(得分:1)
用Json.net做什么呢?
static T CopyPropertiesJson<T>(object source)
{
string jsonsource = JsonConvert.SerializeObject(source);
return JsonConvert.DeserializeObject<T>(jsonsource);
}