Question

该程序旨在将所有数字从1加到我输入的数字。如果我只输入一个数字，答案是正确的，但如果我没有停止并重新打开我的程序，我输入的第二个数字的答案也将添加第一个数字的结果。我错过了什么？请帮忙。

#include<iostream>

using namespace std;

int main()
{
int inNum;
int loopCount = 1;
int count;
int sum = 0;

cout << "Enter a number greater than 0 (less than 1 to quit): " << endl;
cin >> inNum;

while ( inNum >= loopCount) {
    for (count=0 ; count <= inNum ; count++ ){
        sum = sum + count * count; 
    }

    cout << "The sum of the squares from 1 to " << inNum << " is " << sum << endl;

    cout << "Enter a number greater than 0 (less than 1 to quit): " << endl;
    cin >> inNum;
}
}

Answer 1

一种解决方案是将sum的声明移到您的while块中，

// int sum = 0;
while ( inNum >= loopCount) {
  int sum = 0; // <-- or just sum = 0; and keep the declaration outside the loop

另一个（如评论中所述）是在循环体的末尾重置sum。

告诉计算机在打印后清除答案

1 个答案: