我无法解决这个问题。
此查询在sqlServer中运行且没有错误:
SELECT COUNT(tjmm.MAINMISSION_PARTICIPANT_SID)
FROM T_MOVEMENT_LEG ml INNER JOIN
TJ_MVLG_PARTMOV tjmp ON ml.MOVEMENTLEG_SID = tjmp.MOVEMENTLEG_SID INNER JOIN
T_MAIN_MISSION mm INNER JOIN
T_MISSION_PARTICIPANTS mp ON mm.DETCO_MISSIONPARTICIPANT_SID = mp.MISSION_PARTICIPANT_SID INNER JOIN
T_PARTICIPANT_MOVEMENT pm ON mp.MISSION_PARTICIPANT_SID = pm.MISSION_PARTICIPANT_SID INNER JOIN
TJ_MMIS_MISPART tjmm ON mm.MAINMISSION_SID = tjmm.MAINMISSION_SID AND
mp.MISSION_PARTICIPANT_SID = tjmm.MISSION_PARTICIPANT_SID ON
tjmp.PARTICIPANTMOVEMENT_SID = pm.PARTICIPANTMOVEMENT_SID
WHERE (mm.IN_USE = 1) AND (mp.IS_OPS = 1) AND (pm.IS_OPS = 1) AND
(ml.LEGEFFECTIVE_STARTDATE < { fn NOW() }) AND (ml.LEGEFFECTIVE_ENDDATE > { fn NOW() }) AND
(ml.IS_CANCELED = 0)
将其转换为@Formula:
@Formula("select count(tjmm.MAINMISSION_PARTICIPANT_SID) "
+ "FROM T_MOVEMENT_LEG ml INNER JOIN "
+ "TJ_MVLG_PARTMOV tjmp ON ml.MOVEMENTLEG_SID = tjmp.MOVEMENTLEG_SID INNER JOIN "
+ "T_MAIN_MISSION mm INNER JOIN "
+ "T_MISSION_PARTICIPANTS mp ON mm.DETCO_MISSIONPARTICIPANT_SID = mp.MISSION_PARTICIPANT_SID INNER JOIN "
+ "T_PARTICIPANT_MOVEMENT pm ON mp.MISSION_PARTICIPANT_SID = pm.MISSION_PARTICIPANT_SID INNER JOIN "
+ "TJ_MMIS_MISPART tjmm ON mm.MAINMISSION_SID = tjmm.MAINMISSION_SID AND "
+ "mp.MISSION_PARTICIPANT_SID = tjmm.MISSION_PARTICIPANT_SID ON "
+ "tjmp.PARTICIPANTMOVEMENT_SID = pm.PARTICIPANTMOVEMENT_SID "
+ "WHERE (mm.IN_USE = 1) AND (mp.IS_OPS = 1) AND (pm.IS_OPS = 1) AND "
+ "tjmm.MainMission_SID = MainMission_SID AND"
+ "(ml.LEGEFFECTIVE_STARTDATE < NOW()) AND (ml.LEGEFFECTIVE_ENDDATE > NOW()) AND "
+ "(ml.IS_CANCELED = 0)")
private Integer opsCount;
更改了NOW()
并添加了指向pojo Id的链接:tjmm.MainMission_SID = MainMission_SID
任何人都知道我在公式中有哪些错误?
答案 0 :(得分:3)
短篇小说:用大括号包装@Formula的内容
// instead of this
// @Formula("select count(tjmm.MAINMISSION_PARTICIPANT_SID) "
// use this
@Formula("( select count(tjmm.MAINMISSION_PARTICIPANT_SID) "
...
")")
更长的故事:@Formula映射,表示&#34;列类似&#34;表达。如此处所述:
它可以包含任何导致select的语句:
SELECT
column1,
column1 + column2, // expecting columns contain number
column1 * column2,
...
但这不会起作用
SELECT
column1,
...
SELECT count(*) FROM OtherTable, // this won't work
因为这样的陈述必须用大括号包装
SELECT
column1,
...
(SELECT count(*) FROM OtherTable), // working while wrapped with ()
这就是上面@Formula