列出LDAP中的根上下文

时间:2010-04-11 08:40:14

标签: java ldap apacheds

我想列出或搜索LDAP树中的根上下文。我使用Apache Directory Server和Java:

    Hashtable<String, String> contextParams = new Hashtable<String, String>();
    contextParams.put("java.naming.provider.url", "ldap://localhost:10389");
    contextParams.put("java.naming.security.principal", "uid=admin,ou=system");
    contextParams.put("java.naming.security.credentials", "secret");
    contextParams.put("java.naming.security.authentication", "simple");
    contextParams.put("java.naming.factory.initial", "com.sun.jndi.ldap.LdapCtxFactory");

    DirContext dirContext = new InitialDirContext(contextParams);

    NamingEnumeration<NameClassPair> resultList;

    //Works
    resultList = dirContext.list("ou=system");
    while (resultList.hasMore()) {
        NameClassPair result = resultList.next();
        System.out.println(result.getName());
    }

    //Does not work
    resultList = dirContext.list("");
    while (resultList.hasMore()) {
        NameClassPair result = resultList.next();
        System.out.println(result.getName());
    }

我可以列出ou = system的子节点。但我无法列出实际根节点的子节点。我希望这个列表就像Apache Directory Studio一样: alt text http://lesc.se/stackoverflow/ldap_root_contexts.png

1 个答案:

答案 0 :(得分:4)

可以从根节点(RootDSE)的namingContexts属性获取基本DN。代码应如下所示:

Attributes attributes = dirContext.getAttributes( "", new String[]{"namingContexts"} );
Attribute attribute = attributes.get( "namingContexts" );
NamingEnumeration<?> all = attribute.getAll();
while(all.hasMore())
{
    String next = (String)all.next();
    System.out.println(next);
}