Question

我的php / mysql技能很差。我有这张桌子：

      id|ball1|ball2|ball3|ball4|prize|
      |1|    2|    5|   10|    4|    0|
      |2|    5|    9|    4|    1|    0|
      |3|    3|    6|    4|    9|    0|
      |4|    4|    8|    2|    3|    0|
      |5|    8|    9|    4|   10|    0|
      |6|    2|    4|    1|   10|    0|

使用此查询：

$g1=GetRow("SELECT id
     , GROUP_CONCAT(ball ORDER BY ball) balls
FROM 
 ( SELECT id,ball1 ball FROM lottery
   UNION
   SELECT id,ball2 ball FROM lottery
   UNION
   SELECT id,ball3 ball FROM lottery
   UNION
   SELECT id,ball4 ball FROM lottery
 ) x
 WHERE ball IN (2,5,10,4)
 GROUP 
 BY id 
 HAVING COUNT(*) >= 3");

我得到了这个输出：

1 - 2,4,5,10

6 - 2,4,10

我想将collen“prize”更新为1，其中count> = 3 我试过这个：

$sql=sqlQuery("UPDATE lottery set prize=1 where g1=1");

没用。试过这个：

   GetRow("UPDATE lottery set premio=1 where ball ORDER BY ball) balls
  FROM 
     ( SELECT id,ball1 ball FROM lottery
   UNION
   SELECT id,ball2 ball FROM lottery
   UNION
   SELECT id,ball3 ball FROM lottery
   UNION
   SELECT id,ball4 ball FROM lottery
 ) x
WHERE ball IN (2,5,10,4)
GROUP 
BY id 
HAVING COUNT(*) >= 3");

也没用。 THX。

Answer 1

你能试试吗？

UPDATE lottery set prize = '1' where premio = '1' and
IF(ball1 IN(2,5,10,4),1,0)+
IF(ball2 IN(2,5,10,4),1,0)+
IF(ball3 IN(2,5,10,4),1,0)+
IF(ball4 IN(2,5,10,4),1,0) >= 3

远比使用更新和选择一样复杂。

选择php / mysql之后如何更新？

1 个答案: