Question

我正在重构代码，并且已经在我的c＆＃39;中创建了结构。我需要重新标记的代码。例如：

static const unsigned char glyph_065[] = { 
    ... 
};
static const unsigned char glyph_066[] = { ... };
static const unsigned char glyph_067[] = { ... };
static const unsigned char glyph_065[] = { 
   ... 
};
static const unsigned char glyph_066[] = { ... };
static const unsigned char glyph_067[] = { ... };
static const unsigned char glyph_068[] = { ... };
... # then starting at line 300 say
{'A', 38, 20, glyph_065},
{'B', 38, 20, glyph_066},
{'C', 38, 20, glyph_067},
{'A', 38, 20, glyph_065},
{'B', 38, 20, glyph_066},
{'C', 38, 20, glyph_067},
{'D', 38, 20, glyph_068},
...

我想重新索引。采取上述做法：

static const unsigned char glyph_048[] = { 
  ... 
};
static const unsigned char glyph_049[] = { ... };
static const unsigned char glyph_050[] = { ... };
static const unsigned char glyph_051[] = {
  ... 
};
static const unsigned char glyph_052[] = { ... };
static const unsigned char glyph_053[] = { ... };
static const unsigned char glyph_054[] = { ... };
static const unsigned char glyph_055[] = { ... };
... # then starting at line # 300 say. 
{'0', 38, 20, glyph_048},
{'1', 38, 20, glyph_049},
{'2', 38, 20, glyph_050},
{'3', 38, 20, glyph_051},
{'4', 38, 20, glyph_052},
{'5', 38, 20, glyph_053},
{'6', 38, 20, glyph_054},
...

因此，第一个字段是glyph_标签中数字的ascii表示。我想从一个号码开始，只是数数。字面字符只是数字的ASCII表示，因此它将在9以后计算为＆＃39; 7＆＃39;＆＃39; 8＆＃39;，＆＃39; 9＆＃39;，＆＃39;：＆＃39;，＆＃39;;＆＃39; ...

我的脚本知识是BASH，在BASH中这样做会很令人发指。我确定这可以作为两（2）awk个衬垫来处理，或者至少接近它。有人能让我开始吗？

Answer 1

$ awk -v s=48 '!f&&/^{/{c=0;f=1} /glyph_/{sub(/\047[^\047]+\047/,sprintf("\047%c\047",s+c)); sub(/glyph_[[:digit:]]+/,"glyph_"s+c); c++} 1' file
static const unsigned char glyph_48[] = {
    ...
};
static const unsigned char glyph_49[] = { ... };
static const unsigned char glyph_50[] = { ... };
static const unsigned char glyph_51[] = {
   ...
};
static const unsigned char glyph_52[] = { ... };
static const unsigned char glyph_53[] = { ... };
static const unsigned char glyph_54[] = { ... };
... # then starting at line 300 say
{'0', 38, 20, glyph_48},
{'1', 38, 20, glyph_49},
{'2', 38, 20, glyph_50},
{'3', 38, 20, glyph_51},
{'4', 38, 20, glyph_52},
{'5', 38, 20, glyph_53},
{'6', 38, 20, glyph_54},
...

Answer 2

这可以在一行上使用静态const：

num=48
count=0
while read line; do
  if [ $count -lt 300 ]; then
    l=${line/static const unsigned char glyph_.*[]/static const unsigned char glyph_$num[]}
  else
    if [ $count -eq 300 ]; then 
      num=48
    fi
    c=$[ count - 300 ]
    l=${line/[A-Z]/$c}
    l=${l/glyph_*}glyph_$num},
  fi
  echo "$l"
  num=$[ num + 1 ]
  count=$[ count + 1 ]
done <textfile.txt

Answer 3

像这样创建一个gawk脚本：

#!/usr/bin/gawk -f
#

BEGIN { 
        new=NEW_INIT; 
        for (old=OLD_INIT; old<OLD_MAX; old++) {
          oldStr=sprintf("glyph_%03d",old);
          newStr=sprintf("glyph_%03d",new);
          array[oldStr]=newStr; 
          new++ ;
        }
}

{ 
        for (oldStr in array) {
                $0 = gensub(oldStr, array[oldStr], "g", $0);
        }
        print $0
}

运行它发送新号码：

./script.gawk -v OLD_INIT=65 -v OLD_MAX=99 -v NEW_INIT=48 source

如何在标签中使用ascii数字数据重新索引文本文件？

3 个答案: