是否有一种快速方法可以从左到右依次为df
和n1
以及最后n2
填充此矩阵n3
?
df=matrix(, nrow = 3, ncol =3)
rownames(df)<- c("1","2","3")
colnames(df)<- c("A", "B", "C")
n1= seq(1:3)
n2= seq(6:8)
n3= seq(10:12)
答案 0 :(得分:1)
如果你有很多列cbind
,那么一种方法是:
df[] <- do.call(cbind,mget(ls(pattern="n\\d+"))) #here I am assuming that all the objects created follow the pattern `n1`, `n2`, `n3` etc.
df
# A B C
#1 1 6 10
#2 2 7 11
#3 3 8 12
如果您填写data.frame
,例如df1
df1[] <- mget(ls(pattern="n\\d+"))
df1
# A B C
#1 1 6 10
#2 2 7 11
#3 3 8 12
df <- matrix(, nrow = 3, ncol =3)
rownames(df)<- c("1","2","3")
colnames(df)<- c("A", "B", "C")
df1 <- as.data.frame(df)
n1 <- 1:3
n2 <- 6:8
n3 <- 10:12