我在分组数值数组时遇到问题:
我有像这样的数组中的值
var numb = [5,10,11,6,7,18,1,8,2,1,15,12,4,5,3,4,6,7,15,20];
然后按升序排序
var sortedNumb = [1,1,2,3,4,4,5,5,6,6,7,7,8,10,11,12,15,15,18,20];
现在我想创建一组像
这样的数字1-4,5-8,9-12,13-16,17-20
是否可以动态创建组?
答案 0 :(得分:2)
// important code
var numberToGroupOn = 4;
var numb = [5,10,11,6,7,18,1,8,2,1,15,12,4,5,3,4,6,7,15,20];
var srt = numb.slice(0).sort(function(a, b) { return a - b; });
var groupCount = Math.ceil(srt[srt.length-1] / numberToGroupOn);
var grps = {};
for(var i = 1; i <= groupCount; i++)
{
grps[((i*numberToGroupOn)-(numberToGroupOn-1)).toString() + '-' + (i*numberToGroupOn).toString()] =
srt.filter(function(a) {return (a <= i*numberToGroupOn) && (a >= (i*numberToGroupOn)-(numberToGroupOn-1))});
}
// unimportant code to see output in SO snippet
var output = '';
for(var key in grps)
{
output += key + ': ' + grps[key]+'<br>';
}
document.write(output);
&#13;
这会计算出组的数量,然后使用Array.prototype.filter
构建组的字典。
它仅适用于正数。
答案 1 :(得分:0)
代码:假设sortedNumb不为空:)
var sortedNumb = [1,1,2,3,4,4,5,5,6,6,7,7,8,10,11,12,15,15,18,20];
var groups = [[sortedNumb[0]]];
var lastfirstValueInArray = sortedNumb[0];
var i = 1;
var j = 0;
while (i < sortedNumb.length)
{
if (sortedNumb[i] >= lastfirstValueInArray+4 || (sortedNumb[i]%4 == 1 && sortedNumb[i] != lastfirstValueInArray))
{
j++;
lastfirstValueInArray = 1+j*4;
groups[j] = [];
}
groups[j][groups[j].length] = sortedNumb[i];
i++;
}
console.log(groups);
输出
[Array[6], Array[7], Array[3], Array[2], Array[2]]
修改:
您似乎想要一个4人组的范围,如果您想要N
,只需创建一个将其作为参数的函数,并将所有4
替换为代码中的N
=)
答案 2 :(得分:0)
假设1-4,5-8,9-12,13-16,17-20分组意味着你想要5组,第一组(1-4)包含[1,4]中的所有数字间隔;第二个(5-8)包含[5,8]区间内的所有数字,依此类推。
// numbers and intervals must be in ascending order
var numb = [5,10,11,6,7,18,1,8,2,1,15,12,4,5,3,4,6,7,15,20];
// 1-4 , 5-8 , 9-12 , 13-16 , 17-20
var intervals = [4, 8, 12, 16, 20];
numb.sort(function (a, b) {
return a - b;
});
var groups = [];
var j = 0;
for (var i = 0; i < intervals.length; i++) {
var group = [];
while (numb[j] <= intervals[i]) {
group.push(numb[j]);
j++;
}
groups.push(group);
}
console.log(groups);
输出:
[ [ 1, 1, 2, 3, 4, 4 ],
[ 5, 5, 6, 6, 7, 7, 8 ],
[ 10, 11, 12 ],
[ 15, 15 ],
[ 18, 20 ] ]
编辑:阅读关于根据数组中的最大数量计算间隔的注释。
var numb = [5,10,11,6,7,18,1,8,2,1,15,12,4,5,3,4,6,7,15,20];
numb.sort(function (a, b) {
return a - b;
});
var max = numb[numb.length - 1];
// Five groups based on the max value of the array
var increment = max / 5;
var groups = [];
var j = 0;
for (var i = increment; i <= max; i += increment) {
var group = [];
while (numb[j] <= i) {
group.push(numb[j]);
j++;
}
groups.push(group);
}
console.log(groups);
输出:
[ [ 1, 1, 2, 3, 4, 4 ],
[ 5, 5, 6, 6, 7, 7, 8 ],
[ 10, 11, 12 ],
[ 15, 15 ],
[ 18, 20 ] ]