我想问一下,如果有更好的方法可以多次调用一个方法,在每次通话之间延迟5秒。
但我真的想要调用Toas()方法大约7次,并且使用下面的代码,它看起来不正确。
谢谢你们
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
...
CallMultipleToast();
........
private void CallMultipleToast(){
Runnable call_1 = new Runnable() {
@Override
public void run() {
Toast("Message one");
Runnable call_2 = new Runnable() {
@Override
public void run() {
Toast("Message two");
Runnable call_3 = new Runnable() {
@Override
public void run() {
Toast("Message three");
//CAN I ADD MORE
}
};//end call_3
new Handler().postDelayed(call_3, 5000);
}
};//end call_2
new Handler().postDelayed(call_2, 5000);
}
};//end call_1
new Handler().postDelayed(call_1, 5000);
}
private void Toast(String message){
Toast.makeText(this, message, Toast.LENGTH_LONG).show();
}
答案 0 :(得分:3)
也许你可以这样做:
private void CallMultipleToast(){
Thread t = new Thread(){
@Override
public void run(){
try {
for(i=0;i<7;i++){
Toast("Message "+(i+1));
sleep(5000);
}
} catch (InterruptedException ex) {
Log.i("error","thread");
}
}
};
t.start();
}
答案 1 :(得分:0)
试试这个:
final int DELAY= 5000;
int count = 0;
String[] msgs = {"one", "two", "three", "four", "five"};
Handler handler = new Handler();
Runnable runnable = new Runnable() {
@Override
public void run() {
if (count < 5) {
Toast(msgs[count]);
handler.post(runnable);
}
count++;
}
};
handler.postDelayed(runnable, DELAY);