我有两个数组,我需要从较大的数组中删除
$a = array(223 => 6, 381 => 6);
和第二个数组是:
$b = array(array('id' => 45, 'username' => 'rock'), array('id' => 223, 'username' => 'pop'), array('id' => 381, 'username' => 'stock'));
使用print_r(),它们看起来像这样
Array
(
[223] => 6
[381] => 6
)
Array
(
[0] => Array
(
[id] => 45
[username] => rock
)
[1] => Array
(
[id] => 223
[username] => pop
)
[2] => Array
(
[id] => 381
[username] => stock
)
)
如何从$ b数组中删除id!= $ a [keys] 所以在结果中我将有这样的数组
Array
(
[0] => Array
(
[id] => 223
[username] => pop
)
[1] => Array
(
[id] => 381
[username] => stock
)
)
我尝试使用array_diff,array_search和unset,但不知道如何使它工作。
答案 0 :(得分:6)
因此,您希望过滤掉不存在$a[$sub_array["id"]]
的值,其中$sub_array
是$b
的元素:
然后array_filter()
就是您搜索的内容:
$array = array_filter($b, function ($val) use ($a) {
return isset($a[$val["id"]]);
});
答案 1 :(得分:1)
$a = array(223 => 6, 381 => 6);
$b = array(array('id' => 45, 'username' => 'rock'), array('id' => 223, 'username' => 'pop'), array('id' => 381, 'username' => 'stock'));
$keys = array_keys($a);
$new_array = array();
for ($i = 0, $len = count($b); $i < $len; $i++) {
$c = $b[$i];
if (in_array($c['id'], $keys)) {
$new_array[] = $c;
}
}
var_dump($new_array);
答案 2 :(得分:0)
<?php
$a = array(223 => 6, 381 => 6);
$b = array(array('id' => 45, 'username' => 'rock'), array('id' => 223, 'username' => 'pop'), array('id' => 381, 'username' => 'stock'));
$cc = 0;
foreach($b as $bb)
{
$flag = 0;
foreach($a as $k => $aa)
{
if($bb['id'] == $k)
{
$flag=1;
}
}
if($flag == 0)
{
unset($b[$cc]);
}
$cc++;
}
print_r($b);
答案 3 :(得分:0)
您希望首先使用array_keys从$ a获取所有密钥。然后循环遍历$ b并使用in_array,您将知道id是否为$ a键。最后使用unset。
$a = array(223 => 6, 381 => 6);
$aKey = array_keys($a);
$b = array(array('id' => 45, 'username' => 'rock'), array('id' => 223, 'username' => 'pop'), array('id' => 381, 'username' => 'stock'));
foreach ($b as $key => $value)
if (!in_array($value['id'], $aKey))
unset($b[$key]);
print_r($b);