Question

我在这里有一些代码用于我在Python 3.x中制作的基本游戏。如您所见，本地变量＆＃39; code1＆＃39;在我的值之间创建一个随机的两位数字，用于我的保险箱解锁代码的第一部分（稍后在游戏中）。我想做的是以某种方式存储随机整数，所以如果重新访问特定房间，它将显示该函数的第一个输出随机数，而不是保持变化，因为这会打败线索收集的对象。

def corridorOptions():
    code1 = random.randint(30,60)
    corridorChoice = input('> ')
    if corridorChoice == "loose":
        delayedPrint("You lift the loose floorboard up out its place." + '\n')
        delayedPrint("It shifts with hardly any resistance." + '\n')
        delayedPrint("There is a number etched. It reads " + "'" + str(code1) + "'")

干杯。

Answer 1

我建议您在corridorOptions函数中添加一个属性，该函数仅在函数第一次调用时创建初始化

from random import randint def corridorOptions(): if not hasattr(corridorOptions, 'code'): corridorOptions.code = randint(30, 60) print("There is a number etched. It reads '{0:02d}'".format(corridorOptions.code)) corridorOptions() corridorOptions() corridorOptions() corridorOptions() corridorOptions()

<强>输出

There is a number etched. It reads '58' There is a number etched. It reads '58' There is a number etched. It reads '58' There is a number etched. It reads '58' There is a number etched. It reads '58'

如何在Python中的局部变量中存储随机整数？

1 个答案: