Question

当我在Meetup.com上遇到一个聚会小组寻找即将发生的事件时，我最终得到了这个JSON片段，我相信这是在下次聚会安排的时候。

"utc_offset": -21600000,
"time": 1415752200000,
"waitlist_count": 0,
"updated": 1382991416000,

我正在尝试将其转换为Ruby中的人性化日期/时间，但我不确定如何做到这一点？

Answer 1

这里的时间戳似乎是以毫秒为单位。将它们除以1000，ruby可以将秒数转换为时间。

您可以在Ruby中使用Time.at(i)将整数转换为时间。

Time.at(1415752200000/1000) # => 2014-11-12 08:30:00 +0800
Time.at(1382991416000/1000) # => 2013-10-29 04:16:56 +0800

有关详细信息，请参阅http://www.ruby-doc.org/core-2.1.3/Time.html#method-c-at

Answer 2

正如我从你的time对象中理解的那样，它的返回时间（以毫秒为单位）不是日期。

为此，您可以使用 strftime 方法和Time类

进行尝试

seconds = 1415752200000/1000
Time.at(seconds).strftime("%H:%M:%S")
 => "06:00:00"

根据您的要求，您可以修改strftime()方法的格式，例如

Time.at(seconds).strftime("%Y-%B-%d %H:%M:%S")
 => "2014-November-12 06:00:00"

可用的格式选项：

%a - The abbreviated weekday name (“Sun”)

%A - The full weekday name (“Sunday”)

%b - The abbreviated month name (“Jan”)

%B - The full month name (“January”)

%c - The preferred local date and time representation

%d - Day of the month (01..31)

%H - Hour of the day, 24-hour clock (00..23)

%I - Hour of the day, 12-hour clock (01..12)

%j - Day of the year (001..366)

%m - Month of the year (01..12)

%M - Minute of the hour (00..59)

%p - Meridian indicator (“AM” or “PM”)

%S - Second of the minute (00..60)

%U - Week number of the current year, starting with the first Sunday as the first day of the first week (00..53)

%W - Week number of the current year, starting with the first Monday as the firstday of the first week (00..53)

%w - Day of the week (Sunday is 0, 0..6)

%x - Preferred representation for the date alone, no time

%X - Preferred representation for the time alone, no date

%y - Year without a century (00..99)

%Y - Year with century

%Z - Time zone name

%% - Literal “%” character

Meetup.com API活动时间迄今为止？

2 个答案: