Question

概述：

我有限定半径（20英里）的商店。我有客户。如果客户距离商店不到20英里，则客户被分配到该商店。如果一个客户距离超过1个商店不到20英里，则客户被分配到客户花费最多的商店。

以上是实施和工作正常。但现在我有了新的要求，我需要帮助。商店现在限制了最大分配客户数量。所以我的问题是，当一个客户可以被分配到两个商店，并且由于大多数钱花费而假设客户被分配到该商店，但是该商店已经达到了最大分配客户数量。在这种情况下，必须将客户分配到shop2

到目前为止的查询：

-- assigned all customers to all shops
INSERT  INTO #assignment
        SELECT  cd.ap_business_id ,
                cb.customer_id ,
                dist.distance
        FROM    shops cd
                CROSS JOIN customer cb
                JOIN ZipDistance dist ON dist.zip1 = cd.business_zip
                                         AND cb.zip = dist.zip2

-- If customer is assigned to more than one shop, keep the assignment to the shop that is closest to the customer
-- or to the shop where the customer spends most money. Remove other assignments.
;
WITH    CTE
          AS ( SELECT   a.ap_business_id ,
                        a.customer_id ,
                        a.vehicle_id ,
                        ROUND(a.distance, 1) AS distance ,
                        db$.max_dealer_net_sales AS total1 ,
                        b$.max_dealer_net_sales AS total2 ,
                        ROW_NUMBER() OVER ( PARTITION BY a.customer_id ORDER BY ROUND(a.distance,
                                                              1) ASC, ISNULL(c$.max_shop_net_sales,
                                                              0) DESC, a.customer_id ) AS RN
               FROM     #assignment a -- total $ that given Business spend for collision parts
                        LEFT JOIN ( SELECT  ap_business_id ,
                                            SUM(amount) AS max_customer_net_sales
                                    FROM    customer_payments iq
                                    WHERE   iq.close_date > DATEADD(YEAR, -1,
                                                              GETDATE())
                                    GROUP BY iq.ap_business_id
                                  ) c$ ON c$.ap_business_id = a.ap_business_id
               WHERE    a.customer_id IN ( SELECT   vehicle_id
                                           FROM     #assignment aa
                                           GROUP BY aa.customer_id
                                           HAVING   COUNT(*) > 1 )
             )
    DELETE  #assignment
    FROM    #assignment a
            JOIN CTE c ON a.ap_business_id = c.ap_business_id
                          AND a.customer_id = c.customer_id
                          AND c.RN > 1

将客户分配到商店。商店拥有最多的客户

0 个答案: