Question

我的挑战是双重的：

从类似字符串数组中选择单个字符串，但仅限于首先传递布尔测试。
＆＃34;最后＆＃34;我需要将生成的任何/所有字符串连接成一个完整的文本，整个代码必须在Swift中。

插图：信封代码的背面，用于说明逻辑：

    generatedText.text =

    case Int1 <= 50 && Int2 == 50
        return generatedParagraph1 = pick one string at RANDOM from a an array1 of strings

    case Int3 =< 100
        return generatedParagraph2 = pick one string at RANDOM from a an array2 of strings

    case Int4 == 100
        return generatedParagraph3 = pick one string at RANDOM from a an array3 of strings

    ...etc

    default
        return "Nothing to report"

and concatenate the individual generatedParagraphs

尝试：代码在stringArray1,2和3中选择一个随机元素。代码返回的示例：

---＆GT; ＆＃34; Sentence1_c.Sentence2_a.Sentence3_b＆＃34;

问题：我需要代码只在第一次传递布尔值时选择一个元素。这意味着最终的连接字符串（concastString）可以为空，只包含一个或多个元素，具体取决于有多少bool为True。有谁知道怎么做？

import Foundation

var stringArray1 = ["","Sentence1_a.", "Sentence1_b.", "Sentence1_c."]
var stringArray2 = ["","Sentence2_a.", "Sentence2_b.", "Sentence2_c."]
var stringArray3 = ["","Sentence3_a.", "Sentence3_b.", "Sentence3_c."]


let count1 = UInt32(stringArray1.count)-1
let count2 = UInt32(stringArray2.count)-1
let count3 = UInt32(stringArray3.count)-1

var randomNumberOne = Int(arc4random_uniform(count1))+1
var randomNumberTwo = Int(arc4random_uniform(count2))+1
var randomNumberThree = Int(arc4random_uniform(count3))+1

let concatString = stringArray1[randomNumberOne] + stringArray2[randomNumberTwo] + stringArray3[randomNumberThree]

Answer 1

好吧，我没有通过Bool，但是我显示了来自[String]的连续三个随机字符串。我在操场上跑了这个。

import Foundation

var stringArray = [String]()

for var i = 0; i < 100; i++ {
    stringArray.append("text" + "\(i)")
}


func concat (array: [String]) -> String {
    let count = UInt32(stringArray.count)
    let randomNumberOne = Int(arc4random_uniform(count))
    let randomNumberTwo = Int(arc4random_uniform(count))
    let randomNumberThree = Int(arc4random_uniform(count))

    let concatString = array[randomNumberOne] + array[randomNumberTwo] + array[randomNumberThree]

    return concatString
}

let finalString = concat(stringArray)

如果字符串在Swift中传递了逻辑语句，我怎么能连接它？

1 个答案: