Question

在Spring MVC中，我有一个搜索表单。如果用户提交搜索表单，结果应显示在同一页面中。它重定向到同一页面但是我没有从控制器获取JSP中的属性。

qSearch.jsp

<form:form name="quickSearchForm" id="searchFormId" method="POST" action="./searchQuick.html" modelAttribute="searchForm" onsubmit="return validateForm()">
            <table>
                <tr>
                    <th>Change/Defect ID</th><td><form:input type="text" name="identifier" path="identifier"/></td>
                </tr>
            </table>
            <div class="icons">
                <span><button style="left:0px" type="reset" name="clear" style="border-radius: 25px;">CLEAR</button></span>
                <span><button style="right:0px" type="submit" name="submit" style="border-radius: 25px;" >SEARCH</button></span>
            </div>
        </form:form>

                    <hr>
            <div>
                <c:if test="${empty SEARCH_RESULTS_KEY}">
                <table style="border-collapse: collapse;" border="1" class="showResults">
                        <tr>
                            <td colspan="7">No Results found</td>
                        </tr>
                </table>        
                    </c:if>
            <c:if test="${! empty SEARCH_RESULTS_KEY}">
                <table style="border-collapse: collapse;" border="1" class="showResults">
                        <tr>
                            <td colspan="7">Result found</td>
                        </tr>
                </table> 
           </c:if>

控制器

@RequestMapping(value="/qSearch", method = RequestMethod.GET)  
public String getQuickSearchmodel(Model model) {
    System.out.println("Welcome to search tool\n");
    ArchivalIssue archivalIssue=new ArchivalIssue();
    model.addAttribute("searchForm", archivalIssue);
    return "quickSearchPage";   
 }

@RequestMapping(value = "/searchQuick", method = RequestMethod.POST)  
public ModelAndView getAllArchivalIssues(HttpServletRequest request){

    String identifier = request.getParameter("identifier"); 
    List<ArchivalIssue> archivalIssue = archivalIssueService.getAllArchivalIssue(identifier);

        ModelAndView mav = new ModelAndView("redirect:/qSearch");                           //Add model to display results  
        mav.addObject("SEARCH_RESULTS_KEY", archivalIssue);                         //Add result object to model
        return mav; 

}

请有人帮助我，如何在JSP中获得结果。我总是找不到结果。

Answer 1

当返回值包含redirect：prefix时，视图名称的其余部分将被视为重定向URL。浏览器将向此重定向URL发送新请求。因此，将执行映射到此URL的处理程序方法。

只返回与模型属性响应相同的页面。

您是否正在使用JSTL是否需要进行任何更改

${empty param.SEARCH_RESULTS_KEY}

Answer 2

我认为在这种情况下你不应该重定向。因为重定向将为服务器创建新的GET请求。 quickSearchPage和getAllArchivalIssues应该返回相同的视图

@RequestMapping(value = "/searchQuick", method = RequestMethod.POST)  
public ModelAndView getAllArchivalIssues(HttpServletRequest request){

    String identifier = request.getParameter("identifier"); 
    List<ArchivalIssue> archivalIssue = archivalIssueService.getAllArchivalIssue(identifier);

    //return quickSearchPage, so that the client can render the list archivalIssue
    ModelAndView mav = new ModelAndView("quickSearchPage");                          

    mav.addObject("SEARCH_RESULTS_KEY", archivalIssue); //Add result object to model
    return mav; 
}

Spring 3.0：如何重定向到同一页面

2 个答案: