我是codeigniter的新手,我想问一下我在mysql数据库中插入信息的问题。我有一个home.php控制器,我可以通过我的模型从我的数据库中获取数据,发生相反的事情 - >在我的数据库中插入数据,我不能这样做。所以,我有一个控制器功能 - > insertData,调用VIEW - > viewInserts,在这个VIEW中,我有一个从哪里获取插入数据并将其重定向到我的数据库。你能帮我解决吗?我想创建一个模型,它将触发此操作并将其传递给VIEW,但现在我对这个逻辑感到困惑。 insert_batch()函数会这样做吗?
答案 0 :(得分:0)
Very simple
1. call view from controller
2. submit form
3. save data in db or send to data in model here can add data
1. Controller test.php
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class test extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->helper(array('form', 'url'));
$this->load->library('form_validation');
}
public function add()
{
$this->load->view('test');
}
public function save()
{
//write form validation
$this->form_validation->set_rules('fname','First Name','required|min_length[3]');
$this->form_validation->set_rules('lname','Last Name','required|min_length[3]');
if ($this->form_validation->run() == FALSE) {
//error in validation redirect to form
$this->add();
}
else {
$fname = $this->input->post('fname');
$lname = $this->input->post('lname');
$insertData = array ('fname'=> $fname,
'lname'=>$lname );
//save data using model function or save data directly here
/*
$this->load->model('test_model');
$this->test_model->insertRecord($insertData);
*/
$this->db->insert('testtbl',$insertData);
redirect(base_url().'add');
}
}
}?>
2. view test.php
<form id="testFrm" name="testFrm" action="<?php base_url().?>test/save" method="post">
<input type="text" id="fname" name="fname" value="<?php set_value('fname');?>" >
<input type="text" id="lname" name="lname" value="<?php set_value('lname');?>" >
<input type="submit" id="subBtn" name="subBtn" value="Save" >
</form>
3. Model test_model.php
<?php
if (!defined('BASEPATH'))exit('No direct script access allowed');
class Test_Model extends CI_Model {
function insertRecord($insertData) {
$this->db->insert('testtbl',$insertData);
}
}
?>