如何将图像上传到ServiceStack服务？

Question

我有图像的路径，并使用以下代码将其发送到我的服务器;

HttpWebRequest client = (HttpWebRequest)WebRequest.Create("http://212.175.132.168/service/api/upload/cab.jpg");
client.Method = WebRequestMethods.Http.Post; 

// the following 4 rows enable streaming 
client.AllowWriteStreamBuffering = false;
client.SendChunked = true;
client.ContentType = "multipart/form-data;";
client.Timeout = int.MaxValue;

using (FileStream fileStream = System.IO.File.OpenRead (filePath)) {
    fileStream.Copy (client.GetRequestStream ());
}

var response = new StreamReader (client.GetResponse ().GetResponseStream ()).ReadToEnd ();

但是代码不起作用，图像没有附加。我在这里做错了什么？

Answer 1

HttpWebRequest + multipart/form-data需要边界：

将HttpWebRequest与multipart/form-data一起使用时，您需要指定内容的边界。这是相当多的工作，如果您不理解它，很容易导致损坏的上传。但是this question here涵盖了如何执行此操作。

使用PCL ServiceStack.Client：

但是当您使用ServiceStack后端时，最好的方法是在Android应用程序中使用ServiceStack.Client PCL library，这提供了易于使用的JsonServiceClient。 See this example表示使用ServiceStack演示的完整Android版。

所以给出一个简单的上传服务（在服务器端）：

[Route("/upload","POST")]
public class UploadFileRequest
{
    // Example of other properties you can send with the request
    public string[] Tags { get; set; }
}

class MyFileService : Service
{
    public bool Post(UploadFileRequest request)
    {
        // Check a file has been attached
        if(Request.Files == null || Request.Files.Length == 0)
            throw new HttpError(400, "Bad Request", "No file has been uploaded");

        // Save the file
        Request.Files[0].SaveTo(Request.Files[0].FileName);

        // Maybe store the tags (or any other data in the request)
        // request.Tags

        return true;
    }
}

然后在Android应用中使用JsonServiceClient，那么您只需要这样做：

var filename = "cab.jpg"; // The path of the file to upload
var client = new JsonServiceClient("http://212.175.132.168/service/api/");
using(var fileStream = File.OpenRead(filename))
{
    client.PostFileWithRequest<bool>(fileStream, "cab.jpg", new UploadFileRequest { Tags = new[] { "Cab", "Taxis", "NewYork", "Yellow" }});
}

我希望这会有所帮助。