尝试创建按钮,rule
作为按钮上的名称,desc
作为传递的值。但这只是将$name
放在按钮上。我做错了什么?
<?php
$result = mysqli_query($con,"SELECT * FROM db_Rules");
while($row = mysqli_fetch_array($result)) {
$desc = $row['desc'];
$name = $row['rule'];
?>
<button onclick="myFunction($desc)">$name</button>
<br>
<?php
}
?>
答案 0 :(得分:1)
<button onclick="myFunction(<?php echo $desc; ?>)"><?php echo $name; ?></button>
你需要在php
中写出来答案 1 :(得分:1)
您必须echo
PHP变量才能在HTML元素中获取其值。
<button onclick="myFunction(<?php echo $desc;?>)"><?php echo $name;?></button>
答案 2 :(得分:1)
你需要在循环时回显结果。
<button onclick="myFunction(<?php echo $desc; ?>)"><?php echo $name; ?></button>
完整代码:
<?php
$result = mysqli_query($con, "SELECT * FROM db_Rules");
while ($row = mysqli_fetch_array($result)) {
$desc = $row['desc'];
$name = $row['rule'];
?>
<button onclick="myFunction(<?php echo $desc; ?>)"><?php echo $name; ?></button>
<br>
<?php } ?>
或者在php标签中回显它,而不是关闭并再次打开它们:
echo "<button onclick='myFunction($desc)'>$name</button>";
答案 3 :(得分:1)
PHP适用于PHP。使用PHP code block.
<button onclick="myFunction(<?php echo $desc ?>);"><?php echo $name; ?></button>
答案 4 :(得分:1)
您已经忘记在php变量周围添加php标记了。
<?php
$result = mysqli_query($con,"SELECT * FROM db_Rules");
while($row = mysqli_fetch_array($result)) {
$desc = $row['desc'];
$name = $row['rule'];
?>
<button onclick="myFunction(<?php echo $desc;?>)"><?php echo $name;?></button>
<br>
<?php
}
?>
答案 5 :(得分:1)
你没有回应任何东西,只是HTML
<?php
$result = mysqli_query($con,"SELECT * FROM db_Rules");
while($row = mysqli_fetch_array($result)) {
$desc = $row['desc'];
$name = $row['rule'];
?>
<button onclick="myFunction(<?=$desc?>)"><?=$name?></button>
<br>
<?php
}
?>
如果您启用了short_tags,那就是这样。否则
<?php echo $desc; ?>
和
<?php echo $name; ?>
会起作用
答案 6 :(得分:1)
试试这个:
<?php
$result = mysqli_query($con,"SELECT * FROM db_Rules");
while($row = mysqli_fetch_array($result)) {
$desc = $row['desc'];
$name = $row['rule'];
?>
<button onclick="myFunction(<?= $desc?>)"><?= $name?></button>
<br>
<?php
}
?>
问题是,您没有在HTML中回显变量(您的变量未被解释器解析)
答案 7 :(得分:1)
<?php
$result = mysqli_query($con,"SELECT * FROM db_Rules");
while($row = mysqli_fetch_array($result)) {
$desc = $row['desc'];
$name = $row['rule'];
?>
<button onclick="myFunction('<?php echo mysql_real_escape_string($desc)?>')"><?php echo $name;?></button>
<br />
<?php }?>
答案 8 :(得分:1)
注意:如果你想在html中使用php代码那么你应该总是使用php标签
<?php
// Write php code here
?>
这就是为什么你应该替换下面这行
<button onclick="myFunction($desc)">$name</button>
与
<button onclick="myFunction(<?php echo $desc; ?>)"><?php echo $name; ?></button>
,第二种方法是在php标签内写入html
echo '<button onclick="myFunction('.$desc.')">'.$name.'</button>';