我的数据(只是一个例子):
choice1 choice2
--------------------
apple mango
banana apple
mango apple
mango banana
apple banana
我可以使用什么Stata命令获得以下结果,其中choice1
和choice2
的列表合并在一起?
choice number
---------------
apple 4
banana 3
mango 3
choice1
和choice2
是两个独立的字符串变量。
答案 0 :(得分:3)
这是Statalist(www.statalist.org)上讨论的标准问题。一种解决方案是使用SSC上的tabm
包中的用户编写的程序tab_chi
,您应该安装
ssc inst tab_chi
您的示例很容易使用它制表。另一种方法是至少暂时重组数据:
. clear
. input str6 choice1 str6 choice2
choice1 choice2
1. "apple" "mango"
2. "banana" "apple"
3. "mango" "apple"
4. "mango" "banana"
5. "apple" "banana"
6. end
. tabm choice1 choice2, transpose
| variable
values | choice1 choice2 | Total
-----------+----------------------+----------
apple | 2 2 | 4
banana | 1 2 | 3
mango | 2 1 | 3
-----------+----------------------+----------
Total | 5 5 | 10
. d
Contains data
obs: 5
vars: 2
size: 80 (99.9% of memory free)
-----------------------------------------------------------------------------
storage display value
variable name type format label variable label
-----------------------------------------------------------------------------
choice1 str6 %9s
choice2 str6 %9s
-----------------------------------------------------------------------------
Sorted by:
Note: dataset has changed since last saved
. preserve
. stack choice1 choice2, into(choice) clear
. tab choice
choice | Freq. Percent Cum.
------------+-----------------------------------
apple | 4 40.00 40.00
banana | 3 30.00 70.00
mango | 3 30.00 100.00
------------+-----------------------------------
Total | 10 100.00
. restore
. d
Contains data
obs: 5
vars: 2
size: 80 (99.9% of memory free)
-----------------------------------------------------------------------------
storage display value
variable name type format label variable label
-----------------------------------------------------------------------------
choice1 str6 %9s
choice2 str6 %9s
-----------------------------------------------------------------------------
Sorted by:
Note: dataset has changed since last saved
在数据库中搜索提及tabm
的线程是了解更多信息的一种方法。在Stata中search multiple responses
了解其他解决方案和讨论。