在javascript或jquery中查找JSON对象的前5个属性?

时间:2014-09-03 12:24:24

标签: javascript jquery json

我有一个JSON对象,如下所示我希望按日期排序前5个属性。

var json={"09/03/14":"63.7","09/02/14":"67.4","09/01/14":"67.4","08/29/14":"67.4","08/28/14":"69.4","08/27/14":"69.4","08/26/14":"178","08/25/14":"16.8","08/22/14":""} 

2 个答案:

答案 0 :(得分:1)

假设您希望它们按升序日期顺序排序:

var json = {
    "09/03/14": "63.7",
    "09/02/14": "67.4",
    "09/01/14": "67.4",
    "08/29/14": "67.4",
    "08/28/14": "69.4",
    "08/27/14": "69.4",
    "08/26/14": "178",
    "08/25/14": "16.8",
    "08/22/14": ""
}
var arr = [];
for (d in json) {
    arr.push({
        date: new Date(d),
        d: d,
        v: json[d]
    });
}
arr.sort(function (a, b) {
    if (a.date < b.date) {
        return -1;
    }
    if (a.date > b.date) {
        return 1;
    }
    return 0;
});
json = {};
for (var i = 0; i < 5; i++) {
    json[arr[i].d] = arr[i].v;
}
console.log(json);

要按降序排序,请从sort函数交换返回值。另请注意,这不是真正的JSON,它是一个javascript对象文字。

小提琴:http://jsfiddle.net/ccjzzfcr/2/

答案 1 :(得分:0)

<强>样本 Link

  

的Javascript

var json='{"09/03/14":"63.7","09/02/14":"67.4","09/01/14":"67.4","08/29/14":"67.4","08/28/14":"69.4","08/27/14":"69.4","08/26/14":"178","08/25/14":"16.8","08/22/14":"0"}';
var obj= $.parseJSON(json);
for (var prop in obj) {
    $("#res").append("o." + prop + " = " + obj[prop]+"<br />");
     console.log("o." + prop + " = " + obj[prop]);
}
  

更新1:

按照此信息中描述的日期排序。 Sort object by date