Question

我目前正在使用Xcode 6（Beta 6）测试我的应用。 UIActivityViewController适用于iPhone设备和模拟器，但与iPad模拟器和设备（iOS 8）崩溃并带有以下日志

Terminating app due to uncaught exception 'NSGenericException', 
reason: 'UIPopoverPresentationController 
(<_UIAlertControllerActionSheetRegularPresentationController: 0x7fc7a874bd90>) 
should have a non-nil sourceView or barButtonItem set before the presentation occurs.

我正在为iOS 7和iOS 8使用以下iPhone和iPad代码

NSData *myData = [NSData dataWithContentsOfFile:_filename];
NSArray *activityItems = [NSArray arrayWithObjects:myData, nil];
UIActivityViewController *activityViewController = [[UIActivityViewController alloc] initWithActivityItems:nil applicationActivities:nil];
activityViewController.excludedActivityTypes = @[UIActivityTypeCopyToPasteboard];
[self presentViewController:activityViewController animated:YES completion:nil];

我的其他应用程序也遇到了类似的崩溃。你能指导我吗？ iOS 8中的UIActivityViewController有什么变化吗？我查了但是我没有找到任何关于此的内容

Answer 1

在iPad上，活动视图控制器将使用新的UIPopoverPresentationController显示为弹出窗口，它要求您使用以下三个属性之一为弹出窗口的显示指定锚点：

为了指定锚点，您需要获取对UIActivityController的UIPopoverPresentationController的引用，并设置其中一个属性，如下所示：

if ( [activityViewController respondsToSelector:@selector(popoverPresentationController)] ) { 
// iOS8
 activityViewController.popoverPresentationController.sourceView =
parentView;
 }

Answer 2

同样的问题来到我的项目然后我找到了在 iPad 中打开UIActivityViewController的解决方案我们必须使用 UIPopoverController

以下是在iPhone和iPad中使用它的代码

//to attach the image and text with sharing 
UIImage *image=[UIImage imageNamed:@"giraffe.png"];
NSString *str=@"Image form My app";
NSArray *postItems=@[str,image];

UIActivityViewController *controller = [[UIActivityViewController alloc] initWithActivityItems:postItems applicationActivities:nil];

//if iPhone
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
    [self presentViewController:controller animated:YES completion:nil];
}
//if iPad
else {
    // Change Rect to position Popover
    UIPopoverController *popup = [[UIPopoverController alloc] initWithContentViewController:controller];
    [popup presentPopoverFromRect:CGRectMake(self.view.frame.size.width/2, self.view.frame.size.height/4, 0, 0)inView:self.view permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];
}

对于swift 4.2

func openShareDilog() {
    let text = "share text will goes here"

    // set up activity view controller
    let textToShare = [text]
    let activityViewController = UIActivityViewController(activityItems: textToShare, applicationActivities: nil)
    activityViewController.excludedActivityTypes = [.airDrop]

    if let popoverController = activityViewController.popoverPresentationController {
        popoverController.sourceRect = CGRect(x: UIScreen.main.bounds.width / 2, y: UIScreen.main.bounds.height / 2, width: 0, height: 0)
        popoverController.sourceView = self.view
        popoverController.permittedArrowDirections = UIPopoverArrowDirection(rawValue: 0)
    }

    self.present(activityViewController, animated: true, completion: nil)
}

Answer 3

我最近在Swift 2.0中遇到了这个问题（原始问题），其中UIActivityViewController适用于iPhone，但在模拟iPad时会导致崩溃。

我只想在这里添加这个答案的帖子，至少在Swift 2.0中，你不需要if语句。您可以选择popoverPresentationController。

快速地说，接受的答案似乎是说你可以只有一个sourceView，只是一个sourceRect，或者只是一个barButtonItem，但根据Apple's documentation for UIPopoverPresentationController你需要以下其中一个：

barButtonItem
sourceView 和 sourceRect

我正在处理的特定示例如下所示，我正在创建一个函数，该函数接收UIView（对于sourceView和sourceRect）和String（UIActivityViewController的唯一activityItem）。

func presentActivityViewController(sourceView: UIView, activityItem: String ) {

    let activityViewController = UIActivityViewController(activityItems: [activityItem], applicationActivities: [])

    activityViewController.popoverPresentationController?.sourceView = sourceView
    activityViewController.popoverPresentationController?.sourceRect = sourceView.bounds

    self.presentViewController(activityViewController, animated: true, completion: nil)
}

此代码适用于iPhone和iPad（我认为甚至是tvOS） - 如果设备不支持popoverPresentationController，提及它的两行代码基本上都会被忽略。

有点好，你需要做的就是让它适用于iPad只需添加两行代码，或者如果你使用的是barButtonItem就只需要一行代码！

Answer 4

我看到很多人在使用Swift代码时硬编码iPhone / iPad等。

这不是必需的，您必须使用语言功能。以下代码假定您将使用UIBarButtonItem并将在两者 iPhone和iPad上运行。

@IBAction func share(sender: AnyObject) {
    let vc = UIActivityViewController(activityItems: ["hello"], applicationActivities: nil)
    vc.popoverPresentationController?.barButtonItem = sender as? UIBarButtonItem
    self.presentViewController(vc, animated: true, completion: nil)
 }

注意没有If语句或任何其他疯狂的事情。 iPhone上的可选展开将为零，因此行vc.popoverPresentationController?将无法在iPhone上执行任何操作。

Answer 5

使用Xamarin.iOS的解决方案。

在我的示例中，我正在进行屏幕捕获，生成图像，并允许用户共享图像。 iPad上的弹出窗口位于屏幕中间。

var activityItems = new NSObject[] { image };
var excludedActivityTypes = new NSString[] {
    UIActivityType.PostToWeibo,
    UIActivityType.CopyToPasteboard,
    UIActivityType.AddToReadingList,
    UIActivityType.AssignToContact,
    UIActivityType.Print,
};
var activityViewController = new UIActivityViewController(activityItems, null);

//set subject line if email is used
var subject = new NSString("subject");
activityViewController.SetValueForKey(NSObject.FromObject("Goal Length"), subject);

activityViewController.ExcludedActivityTypes = excludedActivityTypes;
//configure for iPad, note if you do not your app will not pass app store review
if(null != activityViewController.PopoverPresentationController)
{
    activityViewController.PopoverPresentationController.SourceView = this.View;
    var frame = UIScreen.MainScreen.Bounds;
    frame.Height /= 2;
    activityViewController.PopoverPresentationController.SourceRect = frame;
}
this.PresentViewController(activityViewController, true, null);

Answer 6

Swift，iOS 9/10（在UIPopoverController弃用之后）

let activityViewController = UIActivityViewController(activityItems: sharingItems, applicationActivities: nil)

    if UIDevice.currentDevice().userInterfaceIdiom == .Pad {

       if activityViewController.respondsToSelector(Selector("popoverPresentationController")) {
          activityViewController.popoverPresentationController?.sourceView = self.view
        }
    }

    self.presentViewController(activityViewController, animated: true, completion: nil)

Answer 7

在Swift中为iPad修复此问题，最好的办法就是这样做，我找到了。

    let things = ["Things to share"]
    let avc = UIActivityViewController(activityItems:things, applicationActivities:nil)
    avc.setValue("Subject title", forKey: "subject")
    avc.completionWithItemsHandler = {
        (s: String!, ok: Bool, items: [AnyObject]!, err:NSError!) -> Void in
    }

    self.presentViewController(avc, animated:true, completion:nil)
    if let pop = avc.popoverPresentationController {
        let v = sender as! UIView // sender would be the button view tapped, but could be any view
        pop.sourceView = v
        pop.sourceRect = v.bounds
    }

Answer 8

修复 Swift 2.0

    if UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone {
        self.presentViewController(activityVC, animated: true, completion: nil)
    }
    else {
        let popup: UIPopoverController = UIPopoverController(contentViewController: activityVC)
        popup.presentPopoverFromRect(CGRectMake(self.view.frame.size.width / 2, self.view.frame.size.height / 4, 0, 0), inView: self.view, permittedArrowDirections: UIPopoverArrowDirection.Any, animated: true)
    }

Answer 9

斯威夫特3：

class func openShareActions(image: UIImage, vc: UIViewController) {
    let activityVC = UIActivityViewController(activityItems: [image], applicationActivities: nil)
    if UIDevice.current.userInterfaceIdiom == .pad {
        if activityVC.responds(to: #selector(getter: UIViewController.popoverPresentationController)) {
            activityVC.popoverPresentationController?.sourceView = vc.view
        }
    }
    vc.present(activityVC, animated: true, completion: nil)
}

Answer 10

夫特：

    let activityViewController = UIActivityViewController(activityItems: sharingItems, applicationActivities: nil)

    //if iPhone
    if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone) {
        self.presentViewController(activityViewController, animated: true, completion: nil)
    } else { //if iPad
        // Change Rect to position Popover
        var popoverCntlr = UIPopoverController(contentViewController: activityViewController)
        popoverCntlr.presentPopoverFromRect(CGRectMake(self.view.frame.size.width/2, self.view.frame.size.height/4, 0, 0), inView: self.view, permittedArrowDirections: UIPopoverArrowDirection.Any, animated: true)

    }

Answer 11

如果您在单击UIActivityViewController时显示UIBarButtonItem，请使用以下代码：

activityViewController.popoverPresentationController?.barButtonItem = sender

否则，如果您使用其他控件，例如UIButton，请使用以下代码：

activityViewController.popoverPresentationController?.sourceView = sender
activityViewController.popoverPresentationController?.sourceRect = sender.bounds

从文档到UIPopoverPresentationController：

var barButtonItem: UIBarButtonItem? { get set }

为此属性分配一个值，以将弹出框锚定到指定的条形按钮项。出现时，弹出框的箭头指向指定的项目。另外，您可以使用sourceView和sourceRect属性指定弹出框的锚点位置。

Answer 12

SwiftUI 版本

func presentActivityView(items: [Any]){
    let activityController = UIActivityViewController(activityItems: items, applicationActivities: nil)
    if UIDevice.current.userInterfaceIdiom == .pad{
        activityController.popoverPresentationController?.sourceView = UIApplication.shared.windows.first
        activityController.popoverPresentationController?.sourceRect = CGRect(x: ScreenSize.width / 3, y: ScreenSize.height / 1.5, width: 400, height: 400)
    }
    UIApplication.shared.windows.first?.rootViewController?.present(activityController, animated: true, completion: nil)
}

Answer 13

swift = ios7 / ios8

let activityViewController = UIActivityViewController(activityItems: sharingItems, applicationActivities: nil)

//if iPhone
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone) {
    // go on..
} else {
    //if iPad
    if activityViewController.respondsToSelector(Selector("popoverPresentationController")) {
        // on iOS8
        activityViewController.popoverPresentationController!.barButtonItem = self.shareButtonItem;
    }
}
self.presentViewController(activityViewController, animated: true, completion: nil)

Answer 14

Hardik Thakkar用 Swift 5 ， XCode 11 回答。

a = [[0, 0, 0, 0, 0, 0],
     [1, 1, 1, 1, 1, 1],
     [2, 2, 2, 2, 2, 2],
     [3, 3, 3, 3, 3, 3],
     [4, 4, 4, 4, 4, 4],
     [5, 5, 5, 5, 5, 5]]

b = [[0, 1, 2, 3, 4, 5],
     [0, 1, 2, 3, 4, 5],
     [0, 1, 2, 3, 4, 5],
     [0, 1, 2, 3, 4, 5],
     [0, 1, 2, 3, 4, 5],
     [0, 1, 2, 3, 4, 5]]

Answer 15

Objective-C解决方案，并使用UIPopoverPresentationController

    UIActivityViewController *controller = /*Init your Controller*/;
    //if iPhone
    if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
        [self presentViewController:controller animated:YES completion:nil];
    }
    //if iPad
    else {
        UIPopoverPresentationController* popOver = controller.popoverPresentationController
        if(popOver){
            popOver.sourceView = controller.view;
            popOver.sourceRect = CGRectMake(self.view.frame.size.width/2, self.view.frame.size.height/4, 0, 0);
            [self presentViewController:controller animated:YES completion:nil];
        }
    }

Answer 16

我找到了这个解决方案首先，呈现弹出窗口的视图控制器应该实现<UIPopoverPresentationControllerDelegate>协议。

接下来，您需要设置popoverPresentationController代表。

添加以下功能：

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
// Assuming you've hooked this all up in a Storyboard with a popover presentation style
    if ([segue.identifier isEqualToString:@"showPopover"]) {
        UINavigationController *destNav = segue.destinationViewController;
        PopoverContentsViewController *vc = destNav.viewControllers.firstObject;

        // This is the important part
        UIPopoverPresentationController *popPC = destNav.popoverPresentationController;
        popPC.delegate = self;
    }
}

- (UIModalPresentationStyle)adaptivePresentationStyleForPresentationController: (UIPresentationController *)controller {
    return UIModalPresentationNone;
}

Answer 17

我正在使用Swift 5。在iPad上的应用程序中单击“共享按钮”时，我也遇到了崩溃的问题。找到了这个解决方案。步骤1：将“视图”对象（在对象库中搜索“ UIView”）添加到Main.storyboard。步骤2：在ViewController.swift中创建一个@IBOutlet并分配任何名称（例如：view1）

第3步：将上述名称（例如：view1）添加为sourceView。这是我的“共享按钮”操作。

@IBAction func Share(_ sender: Any) {
    let activityVC = UIActivityViewController(activityItems: ["www.google.com"], applicationActivities: nil)
    activityVC.popoverPresentationController?.sourceView = view1

    self.present(activityVC, animated: true, completion: nil)


}

我是新手，很快就坚持了一周。希望这会帮助某人。所以分享这个解决方案。

Answer 18

最好的解决这个问题

let urlstring = "https://apps.apple.com/ae/app/"
let text = "some text for your app"
let url = NSURL(string: urlstring)
let textToShare = [url!,text] as [Any]
let activityViewController = UIActivityViewController(activityItems: textToShare as [Any], applicationActivities: nil)
    
activityViewController.excludedActivityTypes = [ UIActivity.ActivityType.airDrop, UIActivity.ActivityType.postToFacebook ,UIActivity.ActivityType.postToFlickr,UIActivity.ActivityType.postToTwitter,UIActivity.ActivityType.postToVimeo,UIActivity.ActivityType.mail,UIActivity.ActivityType.addToReadingList]

activityViewController.popoverPresentationController?.sourceView = self.view
activityViewController.popoverPresentationController?.sourceRect = view.bounds
activityViewController.popoverPresentationController?.permittedArrowDirections = UIPopoverArrowDirection.down
UIApplication.shared.windows.first?.rootViewController?.present(activityViewController, animated: true, completion: nil)

Answer 19

在iphone和ipad中运行的以下代码迅速地4。根据文档

您有责任按照给定的设备习惯用适当的方式展示和关闭视图控制器。 在iPad上，您必须在弹出窗口中显示视图控制器。在其他设备上，必须以模态显示它。

 let activityViewController = UIActivityViewController(activityItems: activityitems, applicationActivities: nil)

    if UIDevice.current.userInterfaceIdiom == .pad {

        if activityViewController.responds(to: #selector(getter: UIViewController.popoverPresentationController)) {
            activityViewController.popoverPresentationController?.sourceView = self.view
        }
    }

    self.present(activityViewController, animated: true, completion: nil)

Answer 20

我尝试了下一个代码并且可行：

首先在View Controller中放置一个条形按钮项然后创建一个IBOutlet：

@property(weak,nonatomic)IBOutlet UIBarButtonItem *barButtonItem;

<。p>下一个.m文件：yourUIActivityViewController.popoverPresentationController.barButtonItem = self.barButtonItem;

Answer 21

对于Swift 2.0。我发现如果你试图将popover锚定到iPad上的分享按钮，这是有效的。这假设您已在工具栏中为共享按钮创建了一个插座。

func share(sender: AnyObject) {
    let firstActivityItem = "test"

    let activityViewController = UIActivityViewController(activityItems: [firstActivityItem], applicationActivities: nil)

    if UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone {
        self.presentViewController(activityViewController, animated: true, completion: nil)
    }
    else {            
        if activityViewController.respondsToSelector("popoverPresentationController") {
            activityViewController.popoverPresentationController!.barButtonItem = sender as? UIBarButtonItem
            self.presentViewController(activityViewController, animated: true, completion: nil)
        }

    }
}

Answer 22

如果您使用swift开发iPad，请小心，它在调试时可以正常工作，但在发布时会崩溃。为了使其与testFlight和AppStore一起使用，请使用-none禁用针对swift的优化以进行发布。

UIActivityViewController在iOS 8 iPad上崩溃

22 个答案: