Question

亲爱的程序员。我必须连接到api并使用我回来的json将它存储在一个表中。使用AFnetworking，Xcode和ios。到目前为止，它已经让我整整一天，让我疯了。我已经尝试了几个教程和项目，但我无法让它工作。

第一个问题是我似乎无法找到我在json中找到的钥匙......

当然我必须解析json，这对我来说不起作用

你能帮我把我的json带到桌子视图吗？

我使用的api是：https://api.9292.nl/0.1/locations?lang=nl-NL&q=amsterd

我在应用程序中收到的json作为输出 {

  "locations": [
    {
      "id": "station-amsterdam-centraal",
      "type": "station",
      "stationId": "asd",
      "stationType": "Station",
      "name": "Amsterdam Centraal",
      "place": {
        "name": "Amsterdam",
        "regionCode": "NH",
        "regionName": "Noord-Holland",
        "showRegion": false,
        "countryCode": "NL",
        "countryName": "Nederland",
        "showCountry": false
      },
      "latLong": {
        "lat": 52.378706,
        "long": 4.900489
      },
      "urls": {
        "nl-NL": "/station-amsterdam-centraal",
        "en-GB": "/en/station-amsterdam-centraal"
      }

等

The code I have right now is:
//
//  ViewController.m
//  9292apiconnection
//
//  Created by TheDutchBeast on 02-09-14.
//  Copyright (c) 2014 Lambregts. All rights reserved.
//

#import "ViewController.h"
#import <AFNetworking/AFNetworking.h>

@interface ViewController ()

@property (strong, nonatomic) NSDictionary *posts;
@property (strong, nonatomic) NSMutableArray *post;

@end

@implementation ViewController

- (void)viewDidLoad
{
    [super viewDidLoad];

    AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
    [manager GET:@"http://api.9292.nl/0.1/locations?lang=nl-NL&q=amsterd" parameters:nil success:^(
       AFHTTPRequestOperation *operation, id responseObject) {
        NSLog(@"JSON: %@", responseObject);
    } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
        NSLog(@"Error: %@", error);
    }];

}

- (void)didReceiveMemoryWarning
{
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}

@end

请帮我定义json代码中的密钥以及如何将这些值放入Xcode，ios中的表中。只需要在表格中显示ID和NAME

请不要链接到教程，因为我已经看过它们了提前致谢

Answer 1

尝试将响应json转换为NSDictionary

NSDictionary *receivedDataDic = [NSJSONSerialization JSONObjectWithData:operation.responseObject options:kNilOptions error:&error];

现在可以使用键名来访问所需的值，例如

NSString * id = [receivedDataDic valueForKey:@"id"];
NSString * name = [receivedDataDic valueForKey:@"name"];

在你想要的地方使用那些变量

在代码中进行这些更改

@interface ViewController ()
{
  NSString * id ,* name;
} 

@property (strong, nonatomic) NSDictionary *posts;
@property (strong, nonatomic) NSMutableArray *post;

@end

@implementation ViewController

- (void)viewDidLoad
{
    [super viewDidLoad];

    AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
    [manager GET:@"http://api.9292.nl/0.1/locations?lang=nl-NL&q=amsterd" parameters:nil success:^(
       AFHTTPRequestOperation *operation, id responseObject) {

         NSDictionary *receivedDataDic = [NSJSONSerialization JSONObjectWithData:operation.responseObject options:kNilOptions error:&error];

         id = [receivedDataDic valueForKey:@"id"];
         name = [receivedDataDic valueForKey:@"name"];

    } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
        NSLog(@"Error: %@", error);
    }];

}

Answer 2

使用AFNetworking时，响应对象是NSDictionary对象，无需转换为NSDictionary

你应该能够像这样解析位置数组。

AFHTTPRequestOperationManager *manager =
  [AFHTTPRequestOperationManager manager];
manager.responseSerializer = [AFJSONResponseSerializer serializer];
[manager GET:@"http://api.9292.nl/0.1/locations?lang=nl-NL&q=amsterd"
    parameters:nil
    success:^(AFHTTPRequestOperation *operation, id responseObject) {
      NSArray *locations = [responseObject objectForKey:@"locations"];
      for (id obj in locations) {
        NSLog(@"id: %@, name: %@", [obj objectForKey:@"id"],
              [obj objectForKey:@"name"]);
      }
  }
  failure:^(AFHTTPRequestOperation *operation,
            NSError *error) { NSLog(@"Error: %@", error); }];

在tableview IOS Xcode中显示JSON

2 个答案: