Question

我正在使用jquery datatables 1.10并尝试搜索和过滤表格。我想使用搜索两个列的搜索文本框和一个复选框来过滤第三列的结果。这是我的数据表：

var url = '@Url.Action("SupportClass1Search", "SupportClass1")';
$('#SupportClass1DataTable').DataTable({
    "serverSide": true,
    "processing": true,
    "ajax": url,
    "ordering": true,
    "dom": '<"top"prl<"clear">>t<"bottom">pi<"clear">',
    "pageLength": 10,
    "autoWidth": false,
    "columns": [
        { // create a link column using the value of the column as the link text
            "data": "SupportClass1Id",
            "width": "20%",
            "render": function (oObj) { return "<a href='#' onclick='editItem(\"" + oObj + "\")'>" + oObj + "</a>"; },
        },
        { "data": "SupportClass1Name", "sWidth": "70%" },
        { // convert boolean values to Yes/No
            "data": "Active",
            "width": "7%",
            "render": function (data, type, full) {
                if (data == true)
                { return 'Yes'; }
                else
                { return 'No'; }
            }
        }
    ]
})

我想根据复选框值过滤第3列（活动）。下面的JS用于过滤表格，但在我输入“是”或“否”时没有取出活动列：

// use an outside search input
oTable = $('#SupportClass1DataTable').DataTable();

$('#btnSearch').click(function () {
    oTable.search($('#txtSearch').val()).draw();
})

另外，我更喜欢单独搜索Active列，有点像这样：

oTable
    .column(2).search('Yes')
    .columns([0,1]).search($('#txtSearch').val())
    .draw();

但这不起作用。任何帮助表示赞赏

Answer 1

您可能希望使用columnfilter插件http://jquery-datatables-column-filter.googlecode.com/svn/trunk/index.html（jQuery Datatables插件），因为它可以完成您所寻求的大部分内容。以下是jsFiddle Demo here中的示例。在这个例子中，我使用2个字段进行文本过滤，第3个是下拉列表

    oTable = $("#myTable").dataTable({
    bInfo: false,
    bSort: false,
    bSortable: false,
        "data": arrayData,
        "columns": [{
        "data": "Emp"
    }, {
        "data": "Name"
    }, {
        "data": "Role"
    }, {
        "data": "Notes"
    }]
}).columnFilter({
    sPlaceHolder : "head:before",
    aoColumns : [{
        type : "text"
    }, {
        type : "text"
    }, {
        type : "select",
        values : arrayRoles
    }]
});

Answer 2

我明白了。使用版本1.10，您必须使用ajax.data：

https://datatables.net/reference/option/ajax.data

在我的初始化中，我使用以下内容为我的ajax调用添加了一个额外的参数：

"ajax": {
    "url": url,
    "data": function (d) {
        d.activeOnly = $('#activeOnly').is(':checked');
    }
},

这是我的完整初始化：

$(document).ready(function () {
    // initialize the data table
    var url = '@Url.Action("SupportClass1Search", "SupportClass1")';
    $('#SupportClass1DataTable').DataTable({
        "serverSide": true,
        "processing": true,
        "ajax": url,
        "ordering": true,
        "dom": '<"top"prl<"clear">>t<"bottom">pi<"clear">',
        "pageLength": 10,
        "autoWidth": false,
        "ajax": {
            "url": url,
            "data": function (d) {
                d.activeOnly = $('#activeOnly').is(':checked');
            }
        },
        "columns": [
            { // create a link column using the value of the column as the link text
                "data": "SupportClass1Id",
                "width": "20%",
                "render": function (oObj) { return "<a href='#' onclick='editItem(\"" + oObj + "\")'>" + oObj + "</a>"; },
            },
            { "data": "SupportClass1Name", "sWidth": "70%" },
            { // convert boolean values to Yes/No
                "data": "Active",
                "width": "7%",
                "render": function (data, type, full) {
                    if (data == true)
                    { return 'Yes'; }
                    else
                    { return 'No'; }
                }
            }
        ]
    })

    oTable = $('#SupportClass1DataTable').DataTable();

    // this is a checkbox outside the datatable 
    // whose value I wanted to pass back to my controller

    $('#activeOnly').click(function () {
        oTable.search($('#txtSearch').val()).draw();
    })

    $('#btnSearch').click(function () {
        oTable.search($('#txtSearch').val()).draw();
    })
});

我使用类作为DataTable的模型。我在这里也添加了activeOnly参数/属性：

/// <summary>
/// this class provides a model to use with JQuery DataTables plugin
/// </summary>
public class jQueryDataTableParamModel
{
    #region DataTable specific properties
    /// <summary>
    /// Request sequence number sent by DataTable,
    /// same value must be returned in response
    /// </summary>       
    public string draw { get; set; }

    /// <summary>
    /// Number of records that should be shown in table
    /// </summary>
    public int length { get; set; }

    /// <summary>
    /// First record that should be shown(used for paging)
    /// </summary>
    public int start { get; set; }
    #endregion

    #region Custom properties

    public bool activeOnly { get; set; }

    #endregion
}

这是我的控制者：

public ActionResult SupportClass1Search(jQueryDataTableParamModel param)
{
    // initialize the datatable from the HTTP request
    var searchString = Request["search[value]"];
    var sortColumnIndex = Convert.ToInt32(Request["order[0][column]"]);
    var sortDirection = Request["order[0][dir]"]; // asc or desc

    // query the database and output to a viewmodel
    var lvm = new SupportClass1SearchViewModel { };
    if (String.IsNullOrEmpty(searchString))
    {
        lvm.SupportClass1List = supportClass1Service.GetAll();
    }
    else
    {
        lvm.SupportClass1List = supportClass1Service.FindBy(t => (t.SupportClass1Name.Contains(searchString))
            && (t.Active.Equals(param.activeOnly) || param.activeOnly == false));
    }

    // do a bunch of stuff and retunr a json string of the data
    return MyJson;
}

现在，当我点击activeOnly复选框并重新绘制传递true或false的表到控制器时。

搜索jquery数据表

2 个答案: