Format指定类型“int *”但参数的类型为“int”

Question

创建打印出Body Mass Index的代码

printf("What is your height in inches?\n");
scanf("%d", height);

printf("What is your weight in pounds?\n");
scanf("%d", weight);

我的身高和体重已初始化为int height，int weight，但程序不允许我运行它，因为它表示int*上的格式为scanf行。为了让这个程序运行，我做错了什么？

Answer 1

scanf需要格式（您的"%d"）以及变量的内存地址，它应该放置已读取的值。 height和weight是int，而不是int的内存地址（这是int *类型'所说的'：指向内存地址的指针int）。您应该使用运算符&将内存地址传递给scanf。

您的代码应为：

printf("What is your height in inches?\n");
scanf("%d", &height);

printf("What is your weight in pounds?\n");
scanf("%d", &weight);

更新：正如The Paramagnetic Croissant所指出的那样，参考不是​​正确的术语。所以我把它改成了记忆地址。

Answer 2

考虑到其他用户的说法，尝试这样的事情;

int height;                  <---- declaring your variables
int weight;
float bmi;                   <---- bmi is a float because it has decimal values

printf("What is your height in inches?\n");
scanf("%d", &height);           <----- don't forget to have '&' before variable you are storing the value in

printf("What is your weight in pounds?\n");
scanf("%d", &weight);


bmi = (weight / pow(height, 2)) * 703;    <---- the math for calculating BMI
printf("The BMI is %f\n", bmi);

（为此你需要包含math.h库。）

Answer 3

scanf从标准输入中读取字符，根据这里的格式说明符"%d"解释整数，并将它们存储在相应的参数中。

要存储它们，您必须指定&variable_name，它将指定应存储输入的地址位置。

您的scanf声明应为：

//For storing value of height
scanf(" %d", &height);
//For storing value of weight
scanf(" %d", &weight);

Answer 4

就像其他人所说的，这是因为当您有一个用scanf读取的原语（例如int）值时，您必须将内存地址传递给该原语值。但是，仅添加尚未提及的内容，对于字符串来说并非如此。

示例1.与原始值一起使用

#include <stdio.h>

int main()
{
    int primitiveInteger; // integer (i.e. no decimals allowed)
    scanf("%i", &primitiveInteger); // notice the address of operator getting the address of the primitiveInteger variable by prepending the variable name with the & (address of) operator.
    printf("Your integer is %i", primitiveInteger); simply printing it out here to the stdout stream (most likely your terminal.)
}

示例2。不使用原始值

#include <stdio.h>

int main()
{
    char *nonPrimitiveString; // initialize a string variable which is NOT a primitive in C
    scanf("%s", nonPrimitiveString); // notice there is no address of operator here
    printf("%s\n", nonPrimitiveString); // prints string
}