Question

现在我的代码使用普通的c库，但我需要使用Caen的.so库，我得到Segmentation故障。这是代码：

from ctypes import *
lib = CDLL('./libcaenhvwrapper.so.5.56')
lib.CAENHVInitSystem.restype = c_int
lib.CAENHVInitSystem.argtypes = [c_int, c_int, c_char_p, c_char_p, c_char_p]
lib.CAENHVGetError.restype = c_int    

CAENHV_SYSTEM_TYPE_t = c_int
sy1527 = CAENHV_SYSTEM_TYPE_t(0)
sy2527 = CAENHV_SYSTEM_TYPE_t(1)
sy4527 = CAENHV_SYSTEM_TYPE_t(2)
sy5527 = CAENHV_SYSTEM_TYPE_t(3)
n568 = CAENHV_SYSTEM_TYPE_t(4)
v65xx = CAENHV_SYSTEM_TYPE_t(5)
n1470 = CAENHV_SYSTEM_TYPE_t(6)
v8100 = CAENHV_SYSTEM_TYPE_t(7)

link = c_int
LINKTYPE_TCPIP = link(0)
LINKTYPE_RS232 = link(1)
LINKTYPE_CAENET = link(2)
LINKTYPE_USB = link(3)
LINKTYPE_OPTLINK = link(4)
LINKTYPE_USB_VCP = link(5)

string15=c_char*15
address=string15('1','3','7','.','1','3','8','.','1','3','.','2','0','3','\0')

userName = c_char_p('user')
passwd = c_char_p('user')
ret_init =  lib.CAENHVInitSystem(0, 0, address, userName, passwd)

当我尝试调用该函数时，我得到了一个分段错误。我认为类型是正确定义的。下面你可以看到一段工作正常的代码。

from ctypes import *
lib2 = CDLL('/lib64/libc.so.6')
string15=c_char*15
address=string15('1','3','7','.','1','3','8','.','1','3','.','2','0','3','\0')
address1=create_string_buffer('137.138.13.203')
address2=c_char_p('137.138.13.200')

userName = c_char_p('user')
passwd = c_char_p('user')

a= lib2.strncmp(address, userName, c_int(4))    
a= lib2.strncmp(userName, address, 4)
a= lib2.strncmp(address2, address, 15)

lib2.printf('%d\n', ret_init)
lib2.printf('%s\n', address)
lib2.printf('%s\n', address1)
lib2.printf('%s\n', address2)
lib2.printf('%d\n', lib2.strlen(address))
lib2.printf('%d\n', lib2.strlen(address1))
lib2.printf('%d\n', lib2.strlen(adrress2))

Answer 1

快速搜索：

CAENHVRESULT CAENHVInitSystem(
const char *SystemName, // In
int     LinkType,
void     *Arg,
const char *UserName,
const char *Password
);

第一个参数id肯定是＆＃34;指向char＆＃34;的指针，你应声明它：

lib.CAENHVInitSystem.argtypes = [c_char_p, c_int, c_int, c_char_p, c_char_p, c_char_p]

另外：

ret_init =  lib.CAENHVInitSystem(0, 0, address, userName, passwd)
#                                ^

您将 NULL 传递为SystemName（在大多数系统上，NULL为((void*)0)）。根据{{3}}，我很快就读到了，这并没有明确支持。

这是第一个调用参数SystemName的函数，必须为用户想要控制的所有HV电源调用

C .so库Python

1 个答案: