Question

我目前正在使用此代码输出结果数组：

<?PHP 
$db = JFactory::getDbo();

//Start date
$startdate = date('2010-05-21');

// End date
$end_date = date("Y-m-d");

$arraystring = '';
while (strtotime($startdate) <= strtotime($end_date)) {

    $query = "SELECT * FROM table1 WHERE FROM_UNIXTIME(tm,'%Y-%m-%d') =  '".$startdate."'";
    $db->setQuery($query);
    $replyAGS = $db->query();
    $my_count = $db->getNumRows();

    $arraystring .= $my_count.', ';

    $startdate = date ("Y-m-d", strtotime("+1 day", strtotime($startdate)));

}

$arraystring = rtrim($arraystring, ', ');
?>

正如您所看到的，我在从特定日期到当前日期的循环中进行数据库查询。假设这个循环是从jan运行的。 2007年1月。 2014年这将意味着2557的总循环，这不会是性能/服务器负载的严重问题?? 有更聪明的方法吗？

Answer 1

请尝试使用此查询：

SELECT  FROM_UNIXTIME(tm,'%Y-%m-%d') AS `Day`
        , COUNT(*) AS Visits 
FROM    `table1`
GROUP BY 
        FROM_UNIXTIME(tm,'%Y-%m-%d')

如果适合你，你必须添加：

WHERE FROM_UNIXTIME(tm,'%Y-%m-%d') > DATE('2010-05-21')

Answer 2

我终于做到了！我认为这是一个合理的解决方案，而不会对服务器资源造成太大压力。

请看一下，看看性能是否合适。请注意，我在while循环中使用了foreach循环，但至少现在我没有在每个循环中查询MySQL ..

<?php
$query = "SELECT FROM_UNIXTIME(tm,'%Y-%m-%d') AS Day, COUNT(*) AS Visits FROM table1 GROUP BY FROM_UNIXTIME(tm,'%Y-%m-%d')";
$db->setQuery($query);
$replyAGS1 = $db->query();
$rowsarray = $db->loadObjectList();

$arrayforyearchart = '';
while (strtotime($startdateforarray) <= strtotime($end_date)) {

$counttouse = 0;
foreach ($rowsarray as $keycount) {
if ($keycount->Day == $startdateforarray) {
$counttouse = $keycount->Visits;
}
}    
        $arrayforyearchart .= $counttouse.', ';
        $startdateforarray = date ("Y-m-d", strtotime("+1 day", strtotime($startdateforarray)));

}
$arrayforyearchart = rtrim($arrayforyearchart, ', ');
?>

修改

这是我制作的优化代码，我只做一个数据库查询和一个循环。我使用智能检测内部循环来检查每天是否缺少结果，如果需要，我将数组填入零值。看这里：

    <?php
    $query = "SELECT FROM_UNIXTIME(tm,'%Y-%m-%d') AS Day, COUNT(*) AS Visits FROM #__cwtraffic GROUP BY FROM_UNIXTIME(tm,'%Y-%m-%d')";
    $db->setQuery($query);
    $replyAGS1 = $db->query();
    $rowsarray = $db->loadObjectList();

    $arrayforyearchart = '';
    $loopcount = 0;

    //Loop START
    foreach ($rowsarray as $keycount) {

    $loopcount = $loopcount + 1;
    if ($loopcount == 1) {
    $startdateforarray = $keycount->Day;

    //Data needed later for chart START
    $startdateUnix = strtotime($keycount->Day);
    $startdateDay = date('j', $startdateUnix);
    $startdateMonth = date('n', $startdateUnix);
    $startdateYear = date('Y', $startdateUnix);
    //Data needed later for chart END
    }

    //Fill the array with zero counts if needed START
    $currentdateinloop = strtotime($keycount->Day);
    $comparedate = strtotime($startdateforarray);
    $datediff = $currentdateinloop - $comparedate;
    $istheregap = floor($datediff/(60*60*24));
    $i=1;
    while ($i <= $istheregap) { 
        $arrayforyearchart .= '0, ';
    $i++;
    }
    //Fill the array with zero counts if needed END

    $arrayforyearchart .= $keycount->Visits.', ';
    $startdateforarray = date ("Y-m-d", strtotime("+1 day", strtotime($startdateforarray)));
    }
    //Loop END


    $arrayforyearchart = rtrim($arrayforyearchart, ', ');
    ?>

Answer 3

我猜测最终的实施，但我建议

首先获取所需的所有记录（您可以自定义查询以便为您提供较少的记录）。

$query = "SELECT * FROM table1";

循环$ result

时

if(isset($count[strtotime($result['tm'])])){
    $count[strtotime($result['tm'])] += 1;
}else{
    $count[strtotime($result['tm'])] = 1;
}

通过这种方式，您可以获得按时间戳分组的数组中的计数。

然后你需要对它进行排序，使其按升序排列

ksort($count);

然后循环数组以获取日期

foreach($count as $date=>$val){
    $_date_count[date('Y-M-d',$date)] = $val;
}

你也做

$arraystring = implode(',',$_date_count);

这是你想要的吗？

Answer 4

您可以将查询更改为以下内容： SELECT * FROM table1 WHERE FROM_UNIXTIME(tm) BETWEEN '" . $startdate . "' AND '" . $end_date . "'。这将选择您提供的时间范围内的所有结果。

接下来，您需要遍历结果并计算每天的结果数量，如下所示：

$query = "SELECT * FROM table1 WHERE FROM_UNIXTIME(tm) BETWEEN '" . $startdate . "' AND '" . $end_date . "'";
$db->setQuery($query);
$counts = array();
while ($result = $db->loadAssoc()) {
    $counts[$result['tm']] = (isset($counts[$result['tm']])) ? ($counts[$result['tm']] + 1) : 1;
}

然后最后在您现有的while循环中，您可以$my_count = (isset($counts[$result['tm']])) ? $counts[$result['tm']] : 0;访问给定日期的结果数量。

这导致：

<?PHP 
$db = JFactory::getDbo();

//Start date
$startdate = '2010-05-21';

// End date
$end_date = date("Y-m-d");

$query = "SELECT * FROM table1 WHERE FROM_UNIXTIME(tm) BETWEEN '" . $startdate . "' AND '" . $end_date . "'";
$db->setQuery($query);
$counts = array();
while ($result = $db->loadAssoc()) {
    $counts[$result['tm']] = (isset($counts[$result['tm']])) ? ($counts[$result['tm']] + 1) : 1;
}

$arraystring = '';
while (strtotime($startdate) <= strtotime($end_date)) {
    $my_count = (isset($counts[$result['tm']])) ? $counts[$result['tm']] : 0;

    $arraystring .= $my_count.', ';

    $startdate = date ("Y-m-d", strtotime("+1 day", strtotime($startdate)));
}

$arraystring = rtrim($arraystring, ', ');
?>

现在，您只有1个查询具有相同的功能。

接下来，我可能会将计数代码移动到它自己的函数中，如下所示：

<?php

function getDayCounts($startdate, $enddate) {
    $query = "SELECT * FROM table1 WHERE FROM_UNIXTIME(tm) BETWEEN '" . $startdate . "' AND '" . $enddate . "'";
    $db->setQuery($query);
    $counts = array();
    while ($result = $db->loadAssoc()) {
        $counts[$result['tm']] = (isset($counts[$result['tm']])) ? ($counts[$result['tm']] + 1) : 1;
    }

    return $counts;
}

$db = JFactory::getDbo();

//Start date
$startdate = '2010-05-21';

// End date
$end_date = date("Y-m-d");

$counts = getDayCounts($startdate, $end_date);

$arraystring = '';
while (strtotime($startdate) <= strtotime($end_date)) {
    $my_count = (isset($counts[$result['tm']])) ? $counts[$result['tm']] : 0;

    $arraystring .= $my_count.', ';

    $startdate = date ("Y-m-d", strtotime("+1 day", strtotime($startdate)));
}

$arraystring = rtrim($arraystring, ', ');

希望这有帮助。

Joomla - 循环中的MySQL查询 - 我想这是不好的做法

4 个答案: