Question

嗨我有一个表格，我想要计算，并通过减去每个列中的值来对结果进行分类。

StartDate          EndDate
09:45              10:30
10:00              12:00
10:30              11:00
11:00              17:00
11:15              12:00

在上表中，我想知道在不到2小时内完成了多少次，在2小时内完成了多少次。结果如下：

Below 2hours       2hours and Above
3                    2

Answer 1

select case when DATEDIFF(HH,start_time,end_time) <1 then 'below one hour'
   when DATEDIFF(HH,start_time,end_time) <2 then 'below 2 hour'
    when DATEDIFF(HH,start_time,end_time) <3 then 'below 3 hour'
     when DATEDIFF(HH,start_time,end_time) <4 then 'below 4 hour'
      when DATEDIFF(HH,start_time,end_time) <5 then 'below 5 hour'
      else 'above 5'
      end  from WU_DATAMART_ETL_LOG

请尝试此代码

Answer 2

您可以使用上面的select语句，但只需添加计数功能，如下所示

select
    count(Below_2hours) AS Below_2hours,
    count(2hours_and_Above) AS 2hours_and_Above from
    (
    select
        case
            when DATEDIFF(HH,start_time,end_time) <2 then 'Below_2hours'
            when DATEDIFF(HH,start_time,end_time) >2 then '2hours_and_Above'
        end  from Table_Name ) AS A

在SQL 2008中使用基于查询结果的Count

2 个答案: