我正在尝试进行多线程上传,但会出错。 我猜想用ftplib使用多线程可能是不可能的吗?
我的代码来了:
class myThread (threading.Thread):
def __init__(self, threadID, src, counter, image_name):
self.threadID = threadID
self.src = src
self.counter = counter
self.image_name = image_name
threading.Thread.__init__(self)
def run(self):
uploadFile(self.src, self.image_name)
def uploadFile(src, image_name):
f = open(src, "rb")
ftp.storbinary('STOR ' + image_name, f)
f.close()
ftp = FTP('host') # connect to host, default port
ftp.login() # user anonymous, passwd anonymous@
dirname = "/home/folder/"
i = 1
threads = []
for image in os.listdir(dirname):
if os.path.isfile(dirname + image):
thread = myThread(i , dirname + image, i, image )
thread.start()
threads.append( thread )
i += 1
for t in threads:
t.join()
获取像
这样的一堆ftplib错误提高error_reply,resp error_reply:200类型设置为I
如果我尝试逐个上传,一切正常
答案 0 :(得分:5)
您是否尝试将连接代码放入线程中?
换句话说,让每个线程与FTP.host()和FTP.login()进行单独的连接。服务器可能不喜欢在单个连接上同时进行多次上载,因为它可能一次解析一个命令并且不能处理第二次上载或“STOR”命令。但是,如果您可以从同一个IP地址进行多个连接,那么您将有单独的会话来发出“STOR”命令。
以下是一个例子:
class myThread (threading.Thread):
def __init__(self, threadID, src, counter, image_name):
###############
#Add ftp connection here!
self.ftp = FTP('host') # connect to host, default port
self.ftp.login() # user anonymous, passwd anonymous@
################
self.threadID = threadID
self.src = src
self.counter = counter
self.image_name = image_name
threading.Thread.__init__(self)
def run(self):
uploadFile(self.src, self.image_name)
def uploadFile(src, image_name):
f = open(src, "rb")
self.ftp.storbinary('STOR ' + image_name, f)
f.close()
dirname = "/home/folder/"
i = 1
threads = []
for image in os.listdir(dirname):
if os.path.isfile(dirname + image):
thread = myThread(i , dirname + image, i, image )
thread.start()
threads.append( thread )
i += 1
for t in threads:
t.join()
看看它是否表现得更好。
P.S。不确定我的所有标签是否都已对齐。