我想使用循环函数来输出n / 2 NewMatrix , NewMatrix< - OldMatrix [,c(i,i + 1)],i = ncol(OldMatrix)。
并将其命名为格式: NewMatrix_i ,以便我可以轻松访问单个矩阵。
OldMatrix
A B C D E F G H I J K
[1,] "1" "1" "C" "F" "F" "B" "F" "F" "1" "1" "4"
[2,] "1" "1" "C" "F" "F" "B" "F" "F" "1" "1" "4"
[3,] "1" "1" "C" "F" "F" "B" "F" "F" "1" "1" "4"
[4,] "5" "5" "C" "F" "F" "B" "F" "F" "1" "1" "4"
[5,] "5" "5" "C" "F" "F" "B" "F" "F" "1" "1" "4"
[6,] "5" "5" "C" "F" "F" "B" "F" "F" "1" "1" "4"
答案 0 :(得分:1)
可能有帮助:
indx <- 1:(ncol(OldMatrix)-1)
lst1 <- setNames(lapply(indx, function(i) OldMatrix[,c(i, i+1)]), paste("NewMatrix",indx, sep="_"))
lst1$NewMatrix_10
# J K
#[1,] "1" "4"
#[2,] "1" "4"
#[3,] "1" "4"
#[4,] "1" "4"
#[5,] "1" "4"
#[6,] "1" "4"