Question

我正在尝试从json文件创建java对象。可以说我有两节课：

Class Parent{
   int parentId;
   .....
   .....
   Child c;

   public Parent(int parentId, Child c){
      this.parentId = parentId;
      this.c = c;
   }

Class Child{
   int childId;
   .....
   .....

   public Child(int childId){
      this.childId = childId;
    }

Child child = new Child(10);
Parent p = new Animal(1,child);

现在假设我有两个json文件：

Parents.json: {"parentId":"1","child":10 } <<10 is the childId used as a reference>>
Children.json: {"childId":10, ...... }

是否有任何java库可以让我找回原来的＆＃39; p＆＃39;这两个文件的（父）对象？

使用引用而不是json，xml库还有更好的解组功能吗？在这种情况下，在xml中表示数据然后尝试解组数据会更容易吗？

更新感谢this question

，我在xml中使用Jaxb

@XmlRootElement(name="parent")
@XmlAccessorType(XmlAccessType.FIELD)
class Parent {

private String parentID;
@XmlJavaTypeAdapter(ChildAdapter.class)
private Child child;

public Parent(){    }

public Child getChild() {
    return child;
}
public void setChild(Child child) {
    this.child = child;
}

public String getParentID() {
    return parentID;
}
public void setParentID(String parentID) {
    this.parentID = parentID;
}
}

@XmlRootElement(name="child")
@XmlAccessorType(XmlAccessType.FIELD)
class Child {
@XmlAttribute
@XmlID
String childID;
String childName;

public Child(){ }
}

Answer 1

您可以使用JAXB来编组XML和Java对象之间的解组。如果您也想使用JSON格式，可以使用Jackson-Framwork，它可以理解JAXB注释。请参阅下面的数据实体示例，该示例适用于JAXB和Jackson。

import java.io.Serializable;
import java.util.List;
import java.util.Vector;

import javax.xml.bind.annotation.XmlElementRef;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class Addresses implements Serializable {

    /**
     * 
     */
    private static final long serialVersionUID = 8612689101962471499L;

    protected List<Address> addresses = new Vector<Address>();

    public Addresses() {

    }

    public Addresses(final List<Address> addresses) {
        setAddresses(addresses);
    }

    /**
     * Unfortunately it isn't possible to return an unmodifiable collection
     * like: {@code return Collections.unmodifiableList(addresses);} since JAXB
     * will call Collection.clear()!
     * 
     * @return
     */
    @XmlElementRef
    public List<Address> getAddresses() {
        return addresses;
    }

    private void setAddresses(List<Address> addresses) {
        /*
         * TODO: Do validation here!
         */
        this.addresses = addresses;
    }

    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result
                + ((addresses == null) ? 0 : addresses.hashCode());
        return result;
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        Addresses other = (Addresses) obj;
        if (addresses == null) {
            if (other.addresses != null)
                return false;
        } else if (!addresses.equals(other.addresses))
            return false;
        return true;
    }
}

Json使用Java中的引用进行反序列化

1 个答案: