Question

我有2个broadcastReceivers和1个简单类 -simple类有1个静态变量 - 从broadcastReceiver1设置静态变量simpleClas.time时，varibale设置为正确的值 - 但是当您尝试从broadcastReceiver2访问simpleClass.time时，静态变量始终保持不变，它仍保留在init值中。那件事怎么可能？最后是静态的

class simpleClass{
public static long time = 0;
}

class broadCastReceiver1 extends BroadcastReceiver{
@Override
    public onReceive(){

     //do some stuff and do an update of time variable
      simpleClass.time = System.currentTimeMillis()/1000;

    }
}

class broadCastReceiver2 extends BroadcastReceiver{
@Override
    public onReceive(){

     //do some stuff and only Read the variable time that was previously modified by broadCastReceiver1 and print the reading

     System.out.println("new Value of time = " + simpleClass.time);
    }
}

假设事件顺序为： broadCastReceiver1 broadCastReceiver2

始终读取时间值到初始值0; 对于broadCastReceiver2，变量始终为0，但在simpleClass类中，时间变量更新！您可以使用可变时间的新值在simpleClass中执行其他操作。

以某种方式，broadCastReceiver2只能看到simpleClass.time的init值。怎么会？任何人都可以解释一下吗？

Answer 1

默认情况下，broadCastReceivers会在新流程上运行，因此无法共享相同的数据。

您需要更改清单定义，以便通过将android:process="string"添加到广播接收器定义

来使它们在同一进程上运行

静态变量不会修改java android

1 个答案: