Question

我目前正致力于酒店预订实践计划（我是Java的新手，所以我通过制作随机程序来练习）对于我的生活，我无法弄清楚为什么这个程序在我输入我的客人数后终止，我在Eclipse中编写了程序，我也在Eclipse中编译程序。任何帮助将不胜感激。

我的代码：

package text;

import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Scanner;
import org.apache.commons.lang3.ArrayUtils;

public class HotelReservations {
    public static void main(String[] args){

        @SuppressWarnings("resource")
        Scanner in = new Scanner(System.in);

        int Guests;
        String Reserved;

        int[] RoomsArray = new int[10];

        RoomsArray[0] = (int) ((10 * Math.random()) - 1);
        RoomsArray[1] = (int) ((10 * Math.random()) - 1);
        RoomsArray[2] = (int) ((10 * Math.random()) - 1);
        RoomsArray[3] = (int) ((10 * Math.random()) - 1);
        RoomsArray[4] = (int) ((10 * Math.random()) - 1);
        RoomsArray[5] = (int) ((10 * Math.random()) - 1);
        RoomsArray[6] = (int) ((10 * Math.random()) - 1);
        RoomsArray[7] = (int) ((10 * Math.random()) - 1);
        RoomsArray[8] = (int) ((10 * Math.random()) - 1);
        RoomsArray[9] = (int) ((10 * Math.random()) - 1);   

        Date Date = new Date( );
            SimpleDateFormat ft = 
            new SimpleDateFormat ("EEE, d MMM yyyy 'at' hh:mm a!");

        System.out.println("Today's date is: " + ft.format(Date));

        System.out.println();

        System.out.println("Enter the number of guests:");
        Guests = in.nextInt();

        if (Guests > 8)
        {
            System.out.println("The maximum amount of guests allowed per room is 8. Please split groups of more than 8 into seperate rooms.");
            System.exit(0);
        } 
        else if (ArrayUtils.contains(RoomsArray, 0))
        {
            System.out.println("A room is available! The closest available room is: Room " + ArrayUtils.indexOf(RoomsArray, 0));
        } 
        else 
        { 
            System.out.println("Sorry, no rooms are available.");
        }

        System.out.println("Would you like to reserve this room? (Yes/No)");
        Reserved = in.nextLine();

        if (Reserved.equals("Yes")) //here is where i changed it, now it will check yes/no
        {
            System.out.println("Hi");
        } else 
        {
            System.out.println("No");
        }
    }   
}

Answer 1

我想您正在尝试使用相同的 scanner 来读取整数和文本的输入

不建议使用相同的扫描仪来读取整数和阅读文字输入

使用不同的扫描仪，如scan1和scan2
scan1表示整数
scan2将下一行作为字符串

Scanner scan1= new Scanner(System.in);
System.out.println(q.nextInt());
Scanner scan2= new Scanner(System.in);
System.out.println(scan2.nextLine());

（初学者）Java程序无缘无故终止

1 个答案: