Question

我已经在这几天工作了......但仍然无法达到我想要的效果。非常感谢任何帮助... ...提前谢谢你。

我有一个存储在$ log中的多数组，当你print_r（$ log）时显示如下：

   Array ( [0] => Array ( [0] => Red [1] => Steel ) 
           [1] => Array ( [0] => Red [1] => Wood ) 
           [2] => Array ( [0] => Blue [1] => Wood ) 
         )

目前我有这个：

$counts = $log;
foreach ($log as $value) {
    foreach ($value as $k  => $v) {
        if (!isset($counts[$k])) $counts[$k] = array();
        if (!isset($counts[$k][$v])) $counts[$k][$v] = 0;
        $counts[$k][$v] += 1;
    }
}

foreach ($counts as $k => $v1) {
    foreach ($v1 as $v => $count) {
        echo "$v => $count <br />";
    }
}

哪个显示器：

0 => Red 
1 => Steel 
Red => 2 
Blue => 1 
0 => Red 
1 => Wood 
Steel => 1 
Wood => 2 
0 => Blue 
1 => Wood

但我真的希望得到最终结果：

<h2>Colors</h2>
Red => 2
Blue => 1

<h2>Materials</h2>
Steel => 1
Wood => 2

Answer 1

如果您使用的是PHP >= 5.5，则可以将array_column()与array_count_values()结合使用：

$colors = array_count_values(array_column($log, 0));
$materials = array_count_values(array_column($log, 1));

See demo

或者，如果您未使用PHP >= 5.5，则可以使用PHP 4, 5：

$colors = $materials = array();
foreach ($log as $a){
    $colors[] = $a[0];
    $materials[] = $a[1];
}

$colors = array_count_values($colors);
$materials = array_count_values($materials);

See demo 2

Click here for sample use case that will work with either method.

Answer 2

我这样做：

<?php

$log = array (
  array('Red', 'Steel'),
  array('Red', 'Wood'),
  array('Blue', 'Wood')
);

$materials = array();
$colors = array();

foreach($log as $line) {
  $colors[$line[0]] = (!isset($colors[$line[0]])) ? 1 : $colors[$line[0]] + 1;
  $materials[$line[1]] = (!isset($materials[$line[1]])) ? 1 : $materials[$line[1]] + 1;
}

?>

<h2>Colors</h2>\n
<?php
foreach ($colors as $color => $amount)
  echo "{$color} => {$amount}<br>\n";
?>
<h2>Materials</h2>\n
<?php
foreach ($materials as $material => $amount)
  echo "{$material} => {$amount}<br>\n";
?>

PHP - 计算二维数组中的重复值，然后仅显示带计数的唯一值

2 个答案: