我正在尝试将一个java哈希函数移植到Ruby,但最终会得到一个与预期不同的哈希。下面是相关的java函数(coldfusion):
public string function hashAdministrator(required string pass) {
MessageDigest = createObject('java','java.security.MessageDigest');
for(i=1; i<=5; i++) {
md = MessageDigest.getInstance('SHA-256');
md.update(pass.getBytes('UTF-8'));
pass = enc(md.digest());
}
return pass;
}
private string function enc(strArr) {
//local.strArr = str.getBytes('UTF-8');
local.hex = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'];
savecontent variable="local.out" {
for (local.item in strArr) {
writeOutput(hex[bitshrn(bitAnd(240,local.item),4)+1]);
writeOutput(hex[bitAnd(15,local.item)+1]);
}
};
return local.out;
}
以下是我的红宝石代码:
# encoding: utf-8
require 'digest/sha2'
class RailoPassword
attr_accessor :pass
def admin_password
password = ''
5.times do
md = Digest::SHA2.new
md.update(self.pass)
password = self.enc(md.digest.bytes.to_a)
end
password
end
def enc(strarr)
hex = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f']
a = ''
strarr.each do |item|
a << hex[((0xF0 & item) >> 4)]
a << hex[(0x0F & item)]
end
a
end
end
ruby中的实际实现:
a = RailoPassword.new
a.pass = 'test1234'
puts 'expected: 0be431aeebf55fdc30296e1224fb80b0edbebcddaedb65fcbad1315e906dde65'
puts "actual: #{a.admin_password}"
预期哈希:0be431aeebf55fdc30296e1224fb80b0edbebcddaedb65fcbad1315e906dde65
返回哈希:937e8d5fbb48bd4949536cd65b8d35c426b80d2f830c5c308e2cdec422ae2244
返回的哈希与我刚从Digest :: SHA2获取十六进制摘要:
相同 1.9.3-p547 :335 > Digest::SHA2.hexdigest('test1234')
=> "937e8d5fbb48bd4949536cd65b8d35c426b80d2f830c5c308e2cdec422ae2244"
非常感谢任何协助。
答案 0 :(得分:1)
你不应该这样做:
password = self.pass
然后
md.update(password)
答案 1 :(得分:1)
此:
def admin_password
password = ''
5.times do
md = Digest::SHA2.new
md.update(self.pass)
password = self.enc(md.digest.bytes.to_a)
end
password
end
与您的CFML逻辑不匹配。它应该是这个(我是一个Ruby新手,如果这不是完美的Ruby,那么道歉):
def admin_password
# password = '' # get rid of this
5.times do
md = Digest::SHA2.new
md.update(self.pass)
self.pass = self.enc(md.digest.bytes.to_a) # update the correct variable here
end
self.pass # and return the correct variable here
end
完成后,两个代码块都返回相同的值0be431aeebf55fdc30296e1224fb80b0edbebcddaedb65fcbad1315e906dde65
而且,坦率地说,如果你也完成了@owlstead的建议并做了一些调试,这对你来说很明显。所以也有一个教训:如果你寻求帮助,请注意所提供的帮助。