EXTJS 5:如何在EXT JS 5中对网格列进行排序

时间:2014-08-08 08:06:21

标签: javascript extjs extjs5

我最近将EXT JS的版本更新为5,并且覆盖doSort功能不再有效。有人知道怎么做?

覆盖范例:

{
    text: 'Custom',
    sortable : true,
    dataIndex: 'customsort',
    doSort: function(state) {
        var ds = this.up('grid').getStore();
        var field = this.getSortParam();
        ds.sort({
            property: field,
            direction: state,
            sorterFn: function(v1, v2){
                v1 = v1.get(field);
                v2 = v2.get(field);

                return v1.length > v2.length ? 1 : (v1.length < v2.length ? -1 : 0);
            }
        });
    }
}

编辑1: 我只是尝试@tomgranerod的解决方案,但me.sortState始终是'undefined'。 所以我这样做是为了更新我的变量:

    sort: function () {
        var me = this,
            grid = me.up('tablepanel'),
            store = grid.store;

        me.sortState = me.sortState === 'ASC' ? 'DESC' : 'ASC';

        Ext.suspendLayouts();
        me.sorting = true;
        store.sort({
            property: me.getSortParam(),
            direction: me.sortState,
            sortFn: function (v1, v2) {
                v1 = v1.get(field);
                v2 = v2.get(field);

                return v1.length > v2.length ? 1 : (v1.length < v2.length ? -1 : 0);
            }
        });
        delete me.sorting;
        Ext.resumeLayouts(true);
    }

但是从不调用sortFn函数。我不知道为什么。 ===&GT; !!!!它适用于EXT JS 5.0.1,但始终不会调用sortFin函数。 !!!!

编辑2: 这是我试图拥有的:

ASC:

if (v1 and v2 are numbers) return v1 > v2;
else if (v1 is a number and v2 a string) return false;
else if (v1 is a string and v2 a number) return true;
else if (v1 and v2 are strings) return v1 > v2;

DESC:

if (v1 and v2 are numbers) return v1 < v2;
else if (v1 is a number and v2 a string) return true;
else if (v1 is a string and v2 a number) return false;
else if (v1 and v2 are strings) return v1 < v2;

4 个答案:

答案 0 :(得分:5)

您正在覆盖私有方法。所以几乎可以预期它会在重大发布后破裂。如果你看http://docs.sencha.com/extjs/5.0.0/apidocs/source/Column2.html#Ext-grid-column-Column,你会发现没有doSort功能了。

Ext的建议方法是使用sortType config可以使用一个函数将您的值转换为自然排序的东西,通常最简单的方法是将其转换为数字。因此,如果你想要稍微不同的东西,你可以修改我发布的代码来做你想做的事情而不会覆盖私有方法。

运行示例:https://fiddle.sencha.com/#fiddle/8km

var store = Ext.create('Ext.data.Store', {
    fields: [{
        name: 'ref',
        sortType: function(str)  {
            // Ext-JS requires that you return a naturally sortable value
            // not your typical comparator function.
            // The following code puts all valid integers in the range 
            // Number.MIN_SAFE_INTEGER and 0
            // And assumes the other values start with T and sorts 
            // them as positive integers               
            var parsed = parseInt(str, 10); 
            if ( isNaN( parsed ) ){
                return parseInt(str.substring(1), 10);
            } else {
                return Number.MIN_SAFE_INTEGER + parsed;
            }          
        }
    }],
    data: {
        'items': [
            {'ref': '1'},
            {'ref': '12'},
            {'ref': 'T0134'},
            {'ref': '121878'},
            {'ref': 'T0134343'},
            {'ref': 'T01POPI'},
            {'ref': '103'},
            {'ref': 'T01'}            
        ]
    },
    proxy: {
        type: 'memory',
        reader: {
            type: 'json',
            rootProperty: 'items'
        }
    }
});

Ext.create('Ext.grid.Panel', {
    title: 'Grid custom',
    store: store,
    columns: [{
        text: 'Reference',
        dataIndex: 'ref',
    }],
    height: 300,
    width: 400,
    renderTo: Ext.getBody()
});

如果您要重复使用此功能,请查看http://spin.atomicobject.com/2012/07/20/simple-natural-sorting-in-extjs/

/** Sort on string length  */
Ext.apply(Ext.data.SortTypes, {
    myCrazySorter: function (str) {
        // Same as above
    }
});

// And use it like
var store = Ext.create('Ext.data.Store', {
    fields: [{
        name: 'ref',
        sortType: 'myCrazySorter'
    }],

答案 1 :(得分:1)

在快速查看Ext.grid.column.Column的源代码之后,与ExtJS 5中的doSort等效的函数似乎是“排序”。我在此示例中使用的sortState参数似乎已在ExtJS 5.0.1中引入。

sort: function () {
            var me = this,
                grid = me.up('tablepanel'),
                direction,
                store = grid.store;

            direction = me.sortState === 'ASC' ? 'DESC' : 'ASC';

            Ext.suspendLayouts();
            me.sorting = true;
            store.sort({
                sorterFn: function (v1, v2) {
                    v1 = v1.get(me.getSortParam());
                    v2 = v2.get(me.getSortParam());

                    return v1.length > v2.length ? 1 : (v1.length < v2.length ? -1 : 0);
                },
                direction: direction
            });
            delete me.sorting;
            Ext.resumeLayouts(true);
        }

然而,Juan Mendes所描述的解决方案比覆盖内部排序功能更安全可行。

答案 2 :(得分:0)

我终于找到了一种在排序过程中比较两个记录的方法:

1)定义自定义列:

Ext.define('Eloi.grid.column.ReferenceColumn', {
    extend : 'Ext.grid.column.Column',

    alias  : 'widget.referencecolumn',

    config : {
        ascSorter  : null,
        descSorter : null
    },

    destroy : function() {
        delete this.ascSorter;
        delete this.descSorter;

        this.callParent();
    },

    /**
     * @param {String} state The direction of the sort, `ASC` or `DESC`
     */
    sort : function(state) {
        var me         = this,
            tablePanel = me.up('tablepanel'),
            store      = tablePanel.store,
            sorter     = this[state === 'ASC' ? 'getAscSorter' : 'getDescSorter']();

        Ext.suspendLayouts();
        this.sorting = true;

        store.sort(sorter, state, 'replace');

        delete this.sorting;
        Ext.resumeLayouts(true);
    },

    getAscSorter : function() {
        var sorter = this.ascSorter;

        if (!sorter) {
            sorter = new Ext.util.Sorter({
                sorterFn  : this.createSorter('ASC'),
                direction : 'ASC'
            });

            this.setAscSorter(sorter);
        }

        return sorter;
    },

    getDescSorter : function() {
        var sorter = this.ascSorter;

        if (!sorter) {
            sorter = new Ext.util.Sorter({
                sorterFn  : this.createSorter('DESC'),
                direction : 'DESC'
            });

            this.setAscSorter(sorter);
        }

        return sorter;
    },

    createSorter : function(state) {
        var dataIndex = this.dataIndex;

        return function(rec1, rec2) {
            var v1   = rec1.get(dataIndex),
                v2   = rec2.get(dataIndex),
                num1 = parseInt(v1),
                num2 = parseInt(v2),
                ret;

            if (num1 && num2) {
                ret = num1 > num2 ? 1 : (num1 < num2 ? -1 : 0);
            } else {
                if (!num1 && !num2) {
                    num1 = parseInt(v1.substr(1));
                    num2 = parseInt(v2.substr(1));

                    ret = num1 > num2 ? 1 : (num1 < num2 ? -1 : 0);
                }
                if (!num1) {
                    ret = 1;
                }
                if (!num2) {
                    ret = -1;
                }
            }

            if (state === 'DESC') {
                ret = ret * -1;
            }

            return ret;
        };
    }
});

2)将新类型设置为网格中的列(带别名),不要忘记正确设置require配置:

columns  : [
        {
            xtype     : 'referencecolumn',
            text      : 'Reference',
            dataIndex : 'ref',
            flex      : 1
        }
    ]

答案 3 :(得分:0)

您需要使用

sorterFn not sortFn