Question

希望有人可以帮助我。所以，我有一些从RedHat从BPMS导入的本地bpmn进程。现在我试图执行它们，以及一些.drl文件，两次尝试都没有成功。这就是我想要的：

     KnowledgeBuilder kbuilder = KnowledgeBuilderFactory.newKnowledgeBuilder();
     Resource ruleFile = ResourceFactory.newFileResource("src/main/resources/rules0.drl");
     Resource ruleFile1 = ResourceFactory.newFileResource("src/main/resources/rules0.drl");
     Resource process1 = ResourceFactory.newFileResource("src/main/resources/Process1.bpmn");
     kbuilder.add(ruleFile,ResourceType.DRL);
     kbuilder.add(ruleFile1,ResourceType.DRL);
     kbuilder.add(process1,ResourceType.BPMN2);

     KnowledgeBase kbase = kbuilder.newKnowledgeBase();

     kbase.addKnowledgePackages(kbuilder.getKnowledgePackages());                       StatefulKnowledgeSession ksession = kbase.newStatefulKnowledgeSession();
     ksession.fireAllRules();
     ksession.startProcess(process1.getSourcePath());

但我也尝试过：

    KieServices kServices = KieServices.Factory.get();
    KieRepository kRepository = kServices.getRepository();
    KieFileSystem kFileSystem = kServices.newKieFileSystem();
     Resource ruleFile = ResourceFactory.newFileResource("src/main/resources/rules0.drl");
    kFileSystem.write(ResourceFactory.newClassPathResource("rules0.drl"));
    KieBuilder kBuilder = kServices.newKieBuilder(kFileSystem);
    kBuilder.add(ruleFile,ResourceType.DRL);
    kBuilder.buildAll();

KieContainer kContainer =
    kServices.newKieContainer(kRepository.getDefaultReleaseId());
    KieBase kBase = kContainer.getKieBase();
    KieSession kisession = kBase.newKieSession();
    int tot = kisession.fireAllRules();

    System.out.println(""+tot);

totalRules为零，规则从未被触发。在这两种情况下，如果我尝试启动进程（并且只有），它将会出现：

线程中的异常＆＃34; main＆＃34; java.lang.AbstractMethodError：org.jbpm.bpmn2.BPMN2ProcessProviderImpl.configurePackageBuilder（Lorg / kie / internal / builder / KnowledgeBuilder;）V

如果我只尝试触发规则，则会发生nothimg并且tot为0.规则是仅执行syso的简单规则。我在这里错过了什么吗？规则在我的maven项目的src / main / resources /上。抱歉这么大的帖子！

Answer 1

似乎你根本没有插入任何事实，所以我相信不会触发任何规则，因为基本上没有要评估的事实。关于启动进程，似乎项目中缺少某些依赖项。确保jbpm-bpmn2位于应用程序的类路径中

HTH

FireAllRules（）和StartProcess（）不生效

1 个答案: