目标:
单击lstView_bbb中的一行(在Test.xaml中)时,返回值应返回到MainWindow类(MainWindow.xaml)。然后,Test.xaml将被关闭。
问题:
我试图找到一个解决方案,来自行的“_a”数据应该转移到MainWIndow,但由于性能问题,它没有那么顺利。我想让它更有效率。
信息:
*我在VS 2013中使用WPF
* MainWIndow.xaml类的返回值为“_a”
<Window x:Class="WpfApplication1.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="350" Width="525">
<Grid>
<Button x:Name="btn_test" Content="Test" HorizontalAlignment="Left" Margin="348,240,0,0" VerticalAlignment="Top" Width="75" Click="btn_test_Click"/>
</Grid>
</Window>
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
namespace WpfApplication1
{
/// <summary>
/// Interaction logic for MainWindow.xaml
/// </summary>
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
private List<aaa> _myList_aaa;
private void btn_test_Click(object sender, RoutedEventArgs e)
{
_myList_aaa = new List<aaa>();
for (int a = 1; a <= 5; a++)
{
aaa myaaa = new aaa();
myaaa._a = a;
myaaa._city = "New Yor";
myaaa._name = "jj jj jj";
_myList_aaa.Add(myaaa);
}
Test myTest = new Test(_myList_aaa);
myTest.ShowDialog();
}
}
public class aaa
{
public int _a { get; set; }
public string _name { get; set; }
public string _city { get; set; }
}
}
---------------------------------------
<Window x:Class="WpfApplication1.Test"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="Test" Height="300" Width="300">
<Grid Background="#FFE5E5E5">
<ListView x:Name="lstView_bbb" SelectionMode="Single" ItemsSource="{Binding}" HorizontalAlignment="Left" Height="111" Margin="35,67,0,0" VerticalAlignment="Top" Width="222">
<ListView.View>
<GridView>
<GridViewColumn Header="name" Width="auto" DisplayMemberBinding="{Binding Path=_name}" TextBlock.TextAlignment="Left" />
<GridViewColumn Header="city" Width="auto" DisplayMemberBinding="{Binding Path=_city}" TextBlock.TextAlignment="Center" />
</GridView>
</ListView.View>
</ListView>
</Grid>
</Window>
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Shapes;
namespace WpfApplication1
{
/// <summary>
/// Interaction logic for Test.xaml
/// </summary>
public partial class Test : Window
{
public Test(IList<aaa> pAAA)
{
InitializeComponent();
lstView_bbb.DataContext = pAAA;
}
}
}
答案 0 :(得分:0)
最简单的方式是在Test
中创建一个属性:
class Test
{
public aaa SelectedItem
{
get
{
return lstView_bbb.SelectedItems[0] as aaa;
}
}
最佳方式是使用ViewModel。将其分配给Test
并使用其他形式的相同ViewModel来获取所选值。
阅读相关的MSDN article。