Question

我在QT中有一个Android应用程序。我想从一个按钮调用android设置。

我在Java中使用了这段代码：

public void usb(View v){
    Intent intent = new Intent();  
    intent.setClassName("com.android.settings", "com.android.settings.DevelopmentSettings");  
    startActivity(intent);  
}

有没有办法使用QT C ++调用android设置？

Answer 1

QAndroidJniObject可以从Qt C ++代码创建JNI对象。

例如：获取活动：

QAndroidJniObject activity =  QAndroidJniObject::callStaticObjectMethod("org/qtproject/qt5/android/QtNative", "activity", "()Landroid/app/Activity;");

例如：创建一个新的Intent：

QAndroidJniObject intent("android/content/Intent","()V");

然后，您可以逐步翻译从C ++执行您的Java代码....

要回答您的具体问题，请复制/粘贴此代码：

QAndroidJniObject activity = QAndroidJniObject::callStaticObjectMethod("org/qtproject/qt5/android/QtNative", "activity", "()Landroid/app/Activity;");   //activity is valid
if ( activity.isValid() )
{
    // Equivalent to Jave code: 'Intent intent = new Intent();'
    QAndroidJniObject intent("android/content/Intent","()V");
    if ( intent.isValid() )
    {
        QAndroidJniObject param1 = QAndroidJniObject::fromString("com.android.settings");
        QAndroidJniObject param2 = QAndroidJniObject::fromString("com.android.settings.DevelopmentSettings");

        if ( param1.isValid() && param2.isValid() )
        {
            // Equivalent to Jave code: 'intent.setClassName("com.android.settings", "com.android.settings.DevelopmentSettings");'
            intent.callObjectMethod("setClassName","(Ljava/lang/String;Ljava/lang/String;)Landroid/content/Intent;",param1.object<jobject>(),param2.object<jobject>());

            // Equivalent to Jave code: 'startActivity(intent);'
            activity.callObjectMethod("startActivity","(Landroid/content/Intent;)V",intent.object<jobject>());
        }
    }
}

...然后投票！ ; - ）

Answer 2

This is how you can open details of specific application (by package id) in Application Manager using Qt:

QAndroidJniObject activity = QAndroidJniObject::callStaticObjectMethod("org/qtproject/qt5/android/QtNative", "activity", "()Landroid/app/Activity;");   //activity is valid
if (activity.isValid())
{
    QAndroidJniObject param = QAndroidJniObject::fromString("package:com.example.mycoolapp");
    // Equivalent to Jave code: 'Uri uri = Uri::parse("...");'
    QAndroidJniObject uri = QAndroidJniObject::callStaticObjectMethod("android/net/Uri", "parse", "(Ljava/lang/String;)Landroid/net/Uri;", param.object<jstring>());
    if (!uri.isValid()) {
        qWarning("Unable to create Uri object");
        return;
    }
    QAndroidJniObject packageName = QAndroidJniObject::fromString("android.settings.APPLICATION_DETAILS_SETTINGS");

    QAndroidJniObject intent("android/content/Intent","(Ljava/lang/String;)V", packageName.object<jstring>());
    if (!intent.isValid()) {
        qWarning("Unable to create Intent object");
        return;
    }
    intent.callObjectMethod("addCategory", "(Ljava/lang/String;)Landroid/content/Intent;", QAndroidJniObject::fromString("android.intent.category.DEFAULT").object<jstring>());
    intent.callObjectMethod("setData", "(Landroid/net/Uri;)Landroid/content/Intent;", uri.object<jobject>());

    activity.callObjectMethod("startActivity","(Landroid/content/Intent;)V",intent.object<jobject>());
}

Answer 3

接受的答案不适用于自定义的Android设置应用程序，并且在我的新Android One手机上也失败，此外，它还会在“开发者”页面上打开。

下面是一个工作代码（Qt 5.12），该代码在第一页上打开默认设置应用程序，并且可以轻松更改为在其他页面上打开：

const QAndroidJniObject ACTION_SETTINGS = QAndroidJniObject::getStaticObjectField("android/provider/Settings",
                                                                                  "ACTION_SETTINGS",
                                                                                  "Ljava/lang/String;");
if (ACTION_SETTINGS.isValid()) {
    const QAndroidIntent intent(ACTION_SETTINGS.toString());
    QtAndroid::startActivity(intent.handle(), 10101);
}

从QT app（com.android.settings）打开android设置

3 个答案: