我试图使用UISearch
栏来查找特定人物的所有对象。我进行了设置,以便每个PFUser
或用户在points
的主对象中都有一个名称对象。当我试图找到用户并且没有任何对象出现时,但在NSLogs中我获得了所有信息。我认为我的问题出在cellForRowAtIndexPath
,但我不知道为什么!
首先我查询:
- (PFQuery *)queryForTable {
PFQuery *query = [PFQuery queryWithClassName:@"points"];
// The key of the PFObject to display in the label of the default cell style
//self.textKey = @"opponent";
// Uncomment the following line to specify the key of a PFFile on the PFObject to display in the imageView of the default cell style
// self.imageKey = @"image";
// Whether the built-in pull-to-refresh is enabled
self.pullToRefreshEnabled = YES;
// Whether the built-in pagination is enabled
self.paginationEnabled = NO;
// The number of objects to show per page
self.objectsPerPage = 50;
//where you set the username to the specific user to get only this user's post.
// If no objects are loaded in memory, we look to the cache first to fill the table
// and then subsequently do a query against the network.
if (self.objects.count == 0) {
query.cachePolicy = kPFCachePolicyCacheThenNetwork;
}
[query orderByDescending:@"createdAt"];
return query;
}
我放置我的酒吧:
-(void)viewDidAppear:(BOOL)animated{
self.searchBar = [[UISearchBar alloc] initWithFrame:CGRectMake(0, 0, self.view.frame.size.width, 44)];
self.tableView.tableHeaderView = self.searchBar;
self.searchController = [[UISearchDisplayController alloc] initWithSearchBar:self.searchBar contentsController:self];
self.searchController.searchResultsDataSource = self;
self.searchController.searchResultsDelegate = self;
self.searchController.delegate = self;
//CGPoint offset = CGPointMake(0, self.searchBar.frame.size.height);
//self.tableView.contentOffset = offset;
self.searchResults = [NSMutableArray array];
}
过滤结果:
-(void)filterResults:(NSString *)searchTerm {
[self.searchResults removeAllObjects];
PFQuery *query = [PFQuery queryWithClassName: @"points"];
[query whereKeyExists:@"name"]; //this is based on whatever query you are trying to accomplish
[query whereKeyExists:@"opponent"]; //this is based on whatever query you are trying to accomplish
[query whereKey:@"name" containsString:searchTerm];
NSArray *results = [query findObjects];
NSLog(@"%@", results);
NSLog(@"%u", results.count);
[self.searchResults addObjectsFromArray:results];
}
-(BOOL)searchDisplayController:(UISearchDisplayController *)controller shouldReloadTableForSearchString:(NSString *)searchString {
[self filterResults:searchString];
return YES;
}
Counting The Objects:
-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {
if (tableView == self.tableView) {
//if (tableView == self.searchDisplayController.searchResultsTableView) {
return self.objects.count;
} else {
return self.searchResults.count;
}
}
- (CGFloat)tableView:(UITableView *)tableView heightForRowAtIndexPath:(NSIndexPath *)indexPath
{
return 110;
}
试图展示一切!:
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath object:(PFObject *)object {
// If you want a custom cell, create a new subclass of PFTableViewCell, set the cell identifier in IB, then change this string to match
// You can access any IBOutlets declared in the .h file from here and set the values accordingly
// "Cell" is the default cell identifier in a new Master-Detail Project
static NSString *CellIdentifier = @"celltag";
UITableViewCell *cell = (UITableViewCell *)[tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil) {
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier];
}
if (tableView != self.searchDisplayController.searchResultsTableView) {
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [object objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[object objectForKey:@"goals"], [object objectForKey:@"assists"], [object objectForKey:@"totalpoints"], [object objectForKey:@"plusminus"], [object objectForKey:@"hits"],[object objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [object objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [object objectForKey:@"name"];
}
if ([tableView isEqual:self.searchDisplayController.searchResultsTableView]) {
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [object objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[object objectForKey:@"goals"], [object objectForKey:@"assists"], [object objectForKey:@"totalpoints"], [object objectForKey:@"plusminus"], [object objectForKey:@"hits"],[object objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [object objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [object objectForKey:@"name"];
}
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [object objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[object objectForKey:@"goals"], [object objectForKey:@"assists"], [object objectForKey:@"totalpoints"], [object objectForKey:@"plusminus"], [object objectForKey:@"hits"],[object objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [object objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [object objectForKey:@"name"];
return cell;
}
答案 0 :(得分:2)
您的cellForRowAtIndexPath
方法中也存在很多错误。
(1)它包含一个奇怪的条件。
a。首先,您要将指针与!=
运算符进行比较:
if (tableView != self.searchDisplayController.searchResultsTableView)
然后您使用isEqual
if ([tableView isEqual:self.searchDisplayController.searchResultsTableView])
虽然任何一种方法都足够,而且这种条件在技术上应该有效,但我最好保持一致;由于cellForRowAtIndexPath
中的tableView包含对指针的引用,因此使用==或!=运算符不仅足够,而且速度更快。
b。同样以这种方式使用两个if是不好的形式,因为您对这两个选项都有if
个语句。相反,我建议使用if-else语句:
if (tableView != self.searchDisplayController.searchResultsTableView) {
...
} else {
...
}
return cell;
c。您的条件是完全没必要的。在两个条件块中都有相同的代码,然后在条件块之后再次使用相同的代码!因此,就目前而言,您可以删除两个if语句,因为if语句之外的最后一个代码是唯一真正执行的代码。
(2)但是你做实际上需要一个条件,即使你当前的那个是多余的。
关于为什么在使用您指定的代码时表格不会发生变化的最主要问题:
由于您正在使用Parse的cellForRowAtIndexPath
方法,因此正在使用- (PFQuery *)queryForTable
中的信息填充行数据,因此当您的代码当前已写入时,对象将是填充此查询的结果:
PFQuery *query = [PFQuery queryWithClassName:@"points"];
当您不搜索时,可以使用从此查询返回的Parse PFObject参数,但在搜索时使用self.searchResults数组的当前索引处的对象,即[self.searchResults objectAtIndex:indexPath.row]
,例如:
if (tableView != self.searchDisplayController.searchResultsTableView) {
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [object objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[object objectForKey:@"goals"], [object objectForKey:@"assists"], [object objectForKey:@"totalpoints"], [object objectForKey:@"plusminus"], [object objectForKey:@"hits"], [object objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [object objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [object objectForKey:@"name"];
} else {
PFObject *searchResult = [self.searchResults objectAtIndex:indexPath.row];
UILabel *game = (UILabel*) [cell viewWithTag:200];
game.text = [NSString stringWithFormat:@"V.s %@", [searchResult objectForKey:@"opponent"]];
UILabel *points = (UILabel*) [cell viewWithTag:201];
points.text = [NSString stringWithFormat:@"Points: %@G, %@A, %@Pts, %@, %@Hits, %@PPG",[searchResult objectForKey:@"goals"], [searchResult objectForKey:@"assists"], [searchResult objectForKey:@"totalpoints"], [searchResult objectForKey:@"plusminus"], [searchResult objectForKey:@"hits"], [return cell; objectForKey:@"ppg"]];
UILabel *date = (UILabel*) [cell viewWithTag:250];
date.text = [searchResult objectForKey:@"date"];
UILabel *name = (UILabel*) [cell viewWithTag:203];
name.text = [searchResult objectForKey:@"name"];
}
return cell;