Question

我使用php和bash生成monit配置文件/etc/monit.conf 我在转义双引号和单一忽略匹配模式规则

时遇到问题

我正在使用php preg_quote()函数来转义用户输入文本我试着用双引号引用字符串并用

转义里面的双引号

\ and \\ => Error: regex parsing error:Trailing backslash
and \\\ => Error: syntax error '\*\?\[\^\]\$\'

## Monitoring log files 
Check file file.log with path /file/path
ignore match  "\\\+\"\*\?\[\^\]\$\(\)\{\}\=\!\<\>\|\:\-"
if match "ERROR" then alert

简单引用相同

## Monitoring log files 
Check file file.log with path /file/path
ignore match  '\\\+\'\*\?\[\^\]\$\(\)\{\}\=\!\<\>\|\:\-'
if match "ERROR" then alert

在php中

$monit_settings['SUPRESS_KEYWORDS'] = base64_encode($_POST['SUPRESS_KEYWORDS']);
write_shell_config_ini($monit_settings, "../config/monit.ini");
$script = "config-generator-monit.sh";              
exec("$script"); // i am using sudo to execute this script

monit.ini

SUPRESS_KEYWORDS="TGljZW5zZSB2YWxpZGF0aW9uIGZhaWx1cmUgLSBJbnZhbGlkIEtleSBvciBSZWdpc3RyYXRpb24gTmFtZQ=="

Bash脚本config-generator-monit.sh

CONFIG_FILE="/path/monit.ini"
if [[ -f $CONFIG_FILE ]]; then
    . $CONFIG_FILE
else
    echo 'Config file not found'
    exit 1
fi
echo -e 'Check file file.log with path /path/file.log' >> /etc/monit.conf
if [[ -z $SUPRESS_KEYWORDS ]]
    then
    echo 'No supression keywords for file.log'
else
    echo 'Supressing keywords' $SUPRESS_KEYWORDS
    echo -e '   ignore match "'`echo $SUPRESS_KEYWORDS | php -R 'echo base64_decode(preg_quote($argn,"\""));'`'"' >> /etc/monit.conf
fi
echo -e '   if match "ERROR" then alert' >> /etc/monit.conf

我在谷歌搜索可能的解决方案，但没有机会

我希望有人在此之前解决了这个问题

linux Monit配置转义匹配模式字符串

0 个答案: