laravel模型中关系的单元检验

时间:2014-07-28 08:30:48

标签: php unit-testing laravel phpunit constraints

我是laravel模型单元测试的新手。所以请查看并告诉我我做错了什么。我的代码如下。我有2个模型User和UserState。

模型用户

public function state()
    {
        return $this->hasOne('UserState');
    }

模型用户状态

public function user()
{
    return $this->belongsTo('User');
}

现在我正在为UserState编写单元测试。如下:

UnitTest UserStateModelTest

public function testUserRelationIsTrue(){
    $user = new User();
    $user->username = 'testusername';
    $user->save();
    $this->assertEquals($user->user_id, $user->state->id);
}

在phpunit测试运行期间,它会生成错误

Illuminate\Database\QueryException: SQLSTATE[23000]: Integrity constraint violation:
1452 Cannot add or update a child row: a foreign key constraint fails

2 个答案:

答案 0 :(得分:0)

如果您真的想测试一种关系方法,您可以做到这一点,甚至无需将模型保存到数据库中。 您仍然仍需要使用RefreshDatabase特征(或DatabaseMigrations特征),否则模型将不会映射到任何表。

# tests/Unit/ParentTest.php
/**
 * Test Parent has HasMany relationship with Child model
 * @test
 */
public function has_many_children_with_parent_id_fk()
{
    $parent = new Parent;
    $foreign_key = 'parent_id';

    // Get the relationship object, not the data collection
    $relationship = $parent->children();
    $related_model = $relationship->getRelated();

    // Assert this is a HasMany relationship
    $this->assertInstanceOf(HasMany::class, $relationship);
    // Assert the related model is Child
    $this->assertInstanceOf(Child::class, $related_model);
    // Assert the foreign key is the one we specified
    // (This can be useful if you do not use the default one)
    $this->assertEquals($foreign_key, $relationship->getForeignKeyName());
    // Assert the foreign key is a column
    // of the database table mapped by the Child model
    $this->assertTrue(Schema::hasColumns($related_model->getTable(), array($foreign_key)));
}
# tests/Unit/ChildTest.php
/**
 * Test Child has belongsTo relationship with Parent model
 * @test
 */
public function belongs_to_parent_with_parent_id_fk()
{
    $child = new Child;
    $foreign_key = 'parent_id';

    // Get the relationship object, not the data collection
    $relationship = $child->parent();
    $related_model = $relationship->getRelated();

    // Assert this is a BelongsTo relationship
    $this->assertInstanceOf(BelongsTo::class, $relationship);
    // Assert the related model is Parent
    $this->assertInstanceOf(Parent::class, $related_model);
    // Assert the foreign key is the one we specified
    // (This can be useful if you do not use the default one)
    $this->assertEquals($foreign_key, $relationship->getForeignKeyName());
    // Assert the foreign key is a column
    // of the database table mapped by the Child model
    $this->assertTrue(Schema::hasColumns($relationship->getParent()->getTable(), array($foreign_key)));
}

这只是少数几个,但是您可以进行自定义声明,以将所有这些内容封装在TestCase中所有测试文件扩展的地方。以下方法适合我的需求

# tests/TestCase.php
public function assertHasManyUsing($related_model, $relationship, $foreign_key)
{
    $this->assertInstanceOf(HasMany::class, $relationship);
    $this->assertInstanceOf($related_model, $relationship->getRelated());
    $this->assertEquals($foreign_key, $relationship->getForeignKeyName());
    $this->assertTrue(Schema::hasColumns($relationship->getRelated()->getTable(), array($foreign_key)));
}

public function assertBelongsToUsing($related_model, $relationship, $foreign_key)
{
    $this->assertInstanceOf(BelongsTo::class, $relationship);
    $this->assertInstanceOf($related_model, $relationship->getRelated());
    $this->assertEquals($foreign_key, $relationship->getForeignKeyName());
    $this->assertTrue(Schema::hasColumns($relationship->getParent()->getTable(), array($foreign_key)));
}

现在,重构测试就像这样

# tests/Unit/ParentTest.php
/**
 * Test Parent has HasMany relationship with Child model
 * @test
 */
public function has_many_children_with_parent_id_fk()
{
    $parent = new Parent;

    $this->assertHasManyUsing(Child::class, $parent->children(), 'parent_id');
}
# tests/Unit/ChildTest.php
/**
 * Test Child has belongsTo relationship with Parent model
 * @test
 */
public function belongs_to_parent_with_parent_id_fk()
{
    $child = new Child;

    $this->assertBelongsToUsing(Parent::class, $child->parent(), 'parent_id');
}

答案 1 :(得分:0)

<块引用>

PHPUnit\Framework\Assert::assertInstanceOf() 的参数 #1 必须是 类或接口名称

tests\TestCase.php:14

>      10▕     use CreatesApplication;
>      11▕
>      12▕     public function assertHasManyUsing($related_model, $relationship, $foreign_key)
>      13▕ {  
>   ➜ 14▕     $this->assertInstanceOf(HasMany::class, $relationship);     
>      15▕     $this->assertInstanceOf($related_model, $relationship->getRelated());
>      16▕     $this->assertEquals($foreign_key, $relationship->getForeignKeyName());
>      17▕     $this->assertTrue(Schema::hasColumns($relationship->getRelated()->getTable(),
> array($foreign_key)));
>      18▕ }