我正在使用PHP制作基本提交表单,将数据提交到mysql数据库 但是我遇到了这个错误
Array ( [asset] => test [bunit] => [winkey] => ) INSERT INTO computers (asset, bunit, winkey) VALUES ('test', ', '')Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '', '')' at line 2
这是我的示例代码,我目前有一些代码用于错误报告和故障排除
<?php
print_r($_POST);
$con=mysqli_connect("lmydbname","myuser","*******","my table");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// escape variables for security
$asset = mysqli_real_escape_string($con, $_POST['asset']);
$bunit= mysqli_real_escape_string($con, $_POST['bunit']);
$winkey = mysqli_real_escape_string($con, $_POST['winkey']);
$sql="INSERT INTO computers (asset, bunit, winkey)
VALUES ('$asset', '$bunit, '$winkey')";
echo $sql;
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
header('Location: nextpage.php');
mysqli_close($con);
?>
答案 0 :(得分:4)
SQL查询中存在语法错误。缺少结束'
:
INSERT INTO computers (asset, bunit, winkey) VALUES ('$asset', '$bunit', '$winkey')
^
答案 1 :(得分:3)
正如Carl所说,您需要发布HTML,因为它看起来似乎没有将值发送到服务器。
但是你在$ bunit
之后错过了你的sql中的'结束' VALUES ('$asset', '$bunit, '$winkey')
答案 2 :(得分:2)
VALUES ('$asset', '$bunit, '$winkey')";
应该是
VALUES ('$asset', '$bunit', '$winkey')";