Question

我已经开始学习python（仅在几天前），而且我仍然坚持使用此代码

# Enter your code for "Car colours" here.
gr = 'Cars that are green: '
si = 'Cars that are silver: '
re = 'Cars that are red: '
wh = 'Cars that are white: '
bl = 'Cars that are blue: '
print(gr, si, re, wh, bl, sep = '\n')
inp = input('Car: ')
while inp:
  Car = inp.split()
  line = input('Car: ')
  print(Car)

我完全不知道从这里到哪里去完成必须提供如下输出的代码

Car: red
Car: white
Car: blue
Car: green
Car: white
Car: silver
Car: 
Cars that are green: 1
Cars that are silver: 1
Cars that are red: 1
Cars that are white: 2
Cars that are blue: 1

任何帮助都会受到赞赏，因为我无法在其他地方找到任何帮助。我正在为GROK做这个代码。

由于

Answer 1

使用字典有帮助：

count = {}
while True:
    color = input('Car: ')
    color = color.lower()
    if not color:
        break
    count.setdefault(color, 0)
    count[color] += 1
for color, n in count.items():
    print('Cars that are %s: %s' % (color, n))

Answer 2

这个答案使用字典，并且仅限于Grok课程中教授的示例代码。

car = {}
color = input("Car: ")

while color:
  if color not in car:
    car[color] = 1
  else:
    car[color] = car[color] + 1
  color = input("Car: ")
for x in car:
  print("Cars that are", x, ":", car[x])

Grok帮助 - 词典

2 个答案: