Question

我在数组中有N个数组，现在N = 3

[[1,2,3, "a","b"] , [3,4,5,"c"], [6,7,8]...]

我想让它返回

[[1,3,6], [2,4,7], [3,5,8], ...., ["a","c", ""], ["b", "",""]]

有很多组合两个数组的解决方案，但我想处理任意数量的数组。我想让它回到上面。我希望在没有下划线或jquery的情况下这样做。

    Values=[];
    status = [[1,2,3, "a","b"] , [3,4,5,"c"], [6,7,8]];
    status_name = status[0]; //take the longest one always
    for (i = 0; i < status_name.length; ++i)
    {
        Values[i] =Array(status_name[i], status[i+1][i]);
    }

Answer 1

从概念上讲，使用嵌套循环最容易实现;

var a = [[1, 2, 'x'], ['a', 'b'], ['+', '-', 'y', 'z']]; // input array

function transform(a) {
    var i, j, // two loops = two variables to iterate with
        foundSomething, // a flag so we know to stop
        b = []; // output array

    i = 0;
    do { // loop for i
        foundSomething = false;
        b[i] = [];
        for (j = 0; j < a.length; ++j) { // loop for j
            if (i in a[j]) { // something exists at this level of i
                foundSomething = true;
                b[i].push(a[j][i]);
            } else { // nothing here
                b[i].push(''); // insert empty string
            }
        }
        ++i;
    } while (foundSomething);
    b.length = b.length - 1; // snip empty end
    return b;
}

transform(a); // [[1, "a", "+"], [2, "b", "-"], ["x", "", "y"], ["", "", "z"]]

需要排序吗？

a.sort(function (a, b) {return a.length < b.length;}); // bigger arrays first
transform(a); // [["+", 1, "a"], ["-", 2, "b"], ["y", "x", ""], ["z", "", ""]]

如果你总是这样做，你可以进一步优化transform，即因为你知道所有a[x].length >= a[y].length x < y，你不需要标记你是否找到了什么

Answer 2

为什么不嵌套循环？

某物。像这个警告伪代码

Values=[];
status = [[1,2,3, "a","b"] , [3,4,5,"c"], [6,7,8];
status_name = status[0]; 


for (i = 0; i < status.length; ++i)
{
    for (k = 0; k < status[i].length; ++i)
    {
        Values[i] =Array(status[i][k], status[k+1][k]);
    }

}

Answer 3

var originalArray = [[1, 2, 3, "a", "b"], [3, 4, 5, "c"], [6, 7, 8]];
var theValues = new Array();
var actualArray = originalArray.pop();
var maxLength = originalArray.length;
while (actualArray) {
  for (var i = 0; i < actualArray.length; i++){
    var newArray = theValues[i];
    if (!newArray) {
      theValues[i] = new Array();
    }
    theValues[i].push(actualArray[i])
  }
  actualArray = originalArray.pop();
}
for (var i = 0; i < theValues.length; i++) {
  for (var j = maxLength - theValues[i].length; j >= 0; j--) {
    theValues[i].push("");
  }
}

javascript：将数组数组合成一个单维多维数组的数组

3 个答案: