Question

我有这个shema：

S_logs =  new mongoose.Schema({
    user_ip : {type: mongoose.Schema.Types.ObjectId},
    user_id : String,
    user_agent : String,
    canal_id :  String,
    theme_id :  String,
    video_id :  String,
    osef : String,
    time : Number,
    action: String,
    is_newuser : String,
    operator : String,
    template : String,
    catalogue : String,
    referer : String,
    from : String,
    osef1 : String
});

我这样填写：

while (i < logs.length) {
    DB_logs[i] = new Model({

        user_ip : logs[i].user_ip,
        user_id : logs[i].user_id,
        user_agent : logs[i].user_agent,
        canal_id :  logs[i].canal_id,
        theme_id :  logs[i].theme_id,
        video_id :  logs[i].video_id,
        osef : logs[i].osef,
        time : logs[i].time,
        action: logs[i].action,
        is_newuser : logs[i].is_newuser,
        operator : logs[i].operator,
        template : logs[i].template,
        catalogue : logs[i].catalogue,
        referer : logs[i].referer,
        from : logs[i].from,
        osef1 : logs[i].osef1
    });
    i = i + 1;
}

没有_id字段，我不明白它有什么用处，但是mongoose似乎希望user_ip被转换为ObjectId，我不想要，user_ip是一个数据字段，而不是索引！

我怎么能：

-Tell mongoose that I do not want a _id
-Auto generate a id for each object?

我做错了什么让mongoose为id获取数据字段？

{ message: 'Cast to ObjectId failed for value "157.55.39.208" at path "user_ip"',
  name: 'CastError',
  type: 'ObjectId',
  value: '157.55.39.208',
  path: 'user_ip' }

Answer 1

这看起来像一个简单的拼写错误：

 user_ip : {type: mongoose.Schema.Types.ObjectId},
 user_id : String,

应该是

user_id : {type: mongoose.Schema.Types.ObjectId},
user_ip : String,

Answer 2

将user_ip作为String

user_ip :String

为什么Mongoose想把我的字符串转换为ObjectId？

2 个答案: